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shepuryov [24]
2 years ago
10

Please, help me!!

Mathematics
2 answers:
uranmaximum [27]2 years ago
8 0

Answer:

16 pounds

Step-by-step explanation:

sin60=x/18

x=15.58

NemiM [27]2 years ago
7 0
50 i’m pretty sure that’s The answer
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Evaluate the expression a + c for a = 22 and c = 11.
bixtya [17]

Answer: 33

Step-by-step explanation: substitute a with 22 and c with 11.

22+11=33

4 0
3 years ago
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Which statement is true about the relation shown on the graph below?
ss7ja [257]

Answer:

b should be the correct one

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5 0
3 years ago
In a certain Algebra 2 class of 30 students, 18 of them play basketball and 9 of them
marshall27 [118]

Probability that a student will play both is 7/30

Step-by-step explanation:

Total students = 30

No. of students who play basketball = 18

Probability that a student will play basketball = 18/30

= 3/5

No. of students who play baseball = 9

Probability that a student will play baseball = 9/30

= 3/10

No. of students who play neither sport = 10

Probability that a student will play neither sport = 10/30

= 1/3

To find :

Probability that a student will play both = p(student will play both)

No.of students who play sport = 30 - 10

= 20

Out of 20 students 18 play basketball and 9 play baseball.

So, some students play both the sports.

No. of students who play both sports = 18 + 9 - 20

= 7

p(student will play both) = 7/30

Probability that a student will play both is 7/30

3 0
3 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
Order from longest side to shortest side.
skad [1K]
The fourth one down is the correct answer trust me
7 0
3 years ago
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