Answer:
11/2n+-1/2p-2
Step-by-step explanation:
simplification
════════ ∘◦❁◦∘ ════════
<h3>Answer = -7</h3>
════════════════════
<h3>Known</h3>
a = 13
U2 = 6
U3 = -1
U4 = -8
════════════════════
<h3>Question</h3>
d = ..?
════════════════════
<h3>Way to do </h3>
#since it gives a lot of number, i will just pick one of the nth term, ill choose U2
Un = a + (n-1)d
U2 = 13 + (2-1)d
6 = 13 + d
6 - 13 = d
d = -7
════════════════════
<h3>Note</h3>
• The formula of arithmetic sequence
<h2>Un = a + (n-1)d</h2>
n = nth term
a = first term
d = common difference
════════════════════
Answer:
- f(x) = x^3
- g(x) = (2x+4)^2
Step-by-step explanation:
There are many ways to decompose h(x) into f(x) and g(x). The main purpose of the exercise seems to be to get you to think about the operations that are performed on x, then divide that list of operations into two parts.
In the function ...
h(x) = (2x +4)^6
the variable x is ...
- multiplied by 2
- 4 is added to the sum
- the sum is raised to the 6th power
Of course, the 6th power can be considered as the cube of a square or the square of a cube, if you like.
In the decomposition shown in the answer above, we have chosen to put most of this list in g(x), including the square of the sum. Then we have made f(x) be the cube of that square.
h(x) = f(g(x)) = (2x+4)^6
When f(x) = x^3, this is ...
h(x) = f(g(x)) = g(x)^3 = ((2x+4)^2)^3
so ...
g(x) = (2x+4)^2 . . . and . . . f(x) = x^3
_____
Other possible decompositions are ...
or
- g(x) = (x+2)
- f(x) = (2x)^6
or
or ... (many others)
Answer:
D
Step-by-step explanation:
6x + 10 = 100
6 times 15 = 90
Add 90 + 10 = 100
