From the information given, each batch of cookies requires 1/6 of a bag of flour.
So how many batches can be gotten from 5/6 of the bag of flour?
We form an equation
1batch = 1/6
x batches = 5/6
Where x is the number of batches from 5/6 bag of flour.
Cross multiplying this equation we get:
x * 1/6 = 1 * 5/6
simplify it:
x * 0.16 = 1 * 0.83
x = 1 * 0.83 / 0.16
x = 0.83 / 0.16
x = 5.2
Therefore factory made approximately 5 batches of cookies yesterday.
Answer:
Step-by-step explanation:
1). In ΔABC,
For angle A as a reference angle,
Opposite side of ∠A → BC
Adjacent side of ∠A → AC
Hypotenuse → AB
2). By using tangent ratio in ΔYWZ,
tan(72°) = 
tan(72°) = 
x = 
x = 3.899
x ≈ 3.9
3). By using sine rule in ΔKNM,
tan(x°) = 
tan(x) = 
x = 
x = 19.03
x ≈ 19.0°
4). By applying cosine ratio in ΔJKF,
tan(70°) = 
tan(70) = 
x = 
x = 21.838
x ≈ 21.8
D has a value of 24.
V121 is 11, so 13 + 11 is 24
Answer:
3.73
Step-by-step explanation:
56/15
3 11/15
3.73