From the information given, each batch of cookies requires 1/6 of a bag of flour.
So how many batches can be gotten from 5/6 of the bag of flour?
We form an equation
1batch  = 1/6
x batches = 5/6
Where x is the number of batches from 5/6 bag of flour. 
Cross multiplying this equation we get:
x * 1/6 = 1 * 5/6
simplify it:
x * 0.16 = 1 * 0.83
x = 1 * 0.83 / 0.16
x = 0.83 / 0.16
x =  5.2
Therefore  factory made approximately 5 batches of cookies yesterday.
 
        
             
        
        
        
Answer:
Step-by-step explanation:
1). In ΔABC,
    For angle A as a reference angle,
    Opposite side of ∠A → BC
    Adjacent side of ∠A → AC
    Hypotenuse → AB
2). By using tangent ratio in ΔYWZ,
     tan(72°) = 
     tan(72°) = 
     x = 
     x = 3.899
     x ≈ 3.9
3). By using sine rule in ΔKNM,
     tan(x°) = 
     tan(x) = 
     x = 
     x = 19.03
     x ≈ 19.0°
4). By applying cosine ratio in ΔJKF,
     tan(70°) = 
     tan(70) = 
     x = 
     x = 21.838
     x ≈ 21.8
 
        
             
        
        
        
D has a value of 24. 
V121 is 11, so 13 + 11 is 24
        
                    
             
        
        
        
Answer:
3.73
Step-by-step explanation:
56/15
3 11/15
3.73