Answer:
67,500 m²
Step-by-step explanation:
ASSUMING the fields look like this __________________
| | |
| | | W
|_________|_________|
L
Let L be the length of the combined field and W be the width
2L + 3W = 1800
2L = 1800 - 3W
L = 900 - 1.5W
A = LW
A = (900 - 1.5W)W
A = 900W - 1.5W²
Area will be maximized when the derivative equals zero.
dA/dW = 900 - 3W
0 = 900 - 3W
3W = 900
W = 300 m
L = 900 - 1.5(300)
L = 450 m
A = LW = 450(300) = 135,000 m²
so each sub field is 135000/2 = 67,500 m²
4x^2-12y^2-6x^2+10y^2
-2x^2-2y^2
i just want points so don't trust me on this
Answer:
f(g(x)) = x^2 + 27.
Step-by-step explanation:
To find f(g(x)) we replace the x in f(x) by g(x) and simplify:
f(g(x)) = 7(x^2 + 2) + 13
= 7x^2 + 14 + 13.
= 7x^2 + 27.
