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Eva8 [605]
3 years ago
5

Find a unit vector that is perpendicular to the vector 5, −4

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

( \frac{4}{ \sqrt{41} } ,  \frac{5}{ \sqrt{41} } )
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Belinda got 18 out of 20 questions correct on a science test. What percent of the questions did Belinda get correct?
oksano4ka [1.4K]
90% im pretty sure if I’m wrong don’t blame me
3 0
3 years ago
If a ball is thrown into the air with a velocity of 38 ft/s, its height in feet t seconds later is given by y = 38t − 16t2. (a)
tiny-mole [99]

Answer:

i.-34ft/s

ii.-27.6ft/s

iii.-26.8ft/s

iv-26.7ft/s

B.-26ft/s

Step-by-step explanation:

average velocity = \frac{y_{2}-y_{1}}{t_{2}-t_{1}}\\

For all cases the value of the initial time t_{1} =2 seconds \\

now we also use this time ti determine the value of the initial height in all cases

y_{1}=38(2)-16(2)^{2} \\y_{1}= 12ft\\

now when the time is increase by 0.5 seconds  the new height becomes

y_{2}=38(2.5)-16(2.5)^{2} \\y_{2}=-5fts\\

the velocity becomes

[tex]Average velocity = \frac{-5-12}{2.5-2}\\Average velocity = -34ft/s\\

ii. when the time is increase by 0.1 seconds

the new height becomes

y_{2}=38(2.1)-16(2.1)^{2} \\y_{2}= 10.66ft\\

Average velocity = \frac{10.66-12}{2.05-2}\\Average velocity = -27.6ft/s\\

iii. when the time is increase by 0.05 seconds

the new height becomes

y_{2}=38(2.05)-16(2.05)^{2} \\y_{2}= 9.24ft\\

Average velocity = \frac{9.24-12}{2.05-2}\\Average velocity = -26.8ft/s\\

iv.  when the time is increase by 0.1 seconds

the new height becomes

y_{2}=38(2.01)-16(2.01)^{2} \\y_{2}= 11.73ft\\

Average velocity = \frac{11.73-12}{2.01-2}\\Average velocity = -26.7ft/s\\.

B. For us to determine the instantaneous velocity expression, we differentiate the expressing for the height

V_{inst}=38-32t\\

we now substitute t=2, we arrive at

V_{inst}=-26ft/s\\

6 0
4 years ago
Find the quadratic equations whose roots are 3 and -4<br>​
Alisiya [41]

Answer:

Hello,

Step-by-step explanation:

(x-3)*(x+4)=0 or <u>x²+x-12=0</u>

4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!!!!!!
Ainat [17]

Answer:

A.measure of centre?

measure of spread is Independent variable ie y and dependent variable is x

B.measure canter integers

measure spread is variable x

I hope it helped

7 0
3 years ago
Which category of two-dimensional shapes apply to all three of these shapes?
earnstyle [38]
A quadrilateral is the category
7 0
3 years ago
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