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Temka [501]
3 years ago
13

Factor x^2 + 5x + 10

Mathematics
1 answer:
White raven [17]3 years ago
7 0
There are no common factors, therefore, it can't be factored. My advice would be to try simplifying and then try factoring. Because this you can't factor.
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Printing signs costs $28 for the design plates plus $2 per sign. Which equation correctly describes the cost, c, of s signs?
Dmitriy789 [7]

Answer:

Step-by-step explanation:

8 0
2 years ago
Find the number of real number solutions for the equation x^2-3+8=0
svlad2 [7]
Find value of determinant.
The determinant is a term that is inside a square root and part of the quadratic formula used for solving quadratic equations.
Let determinant be 'd'.
If d >0, Then there are 2 real solutions
If d = 0, Then there is only 1 real solutions
If d < 0, Then there are 0 real solutions but 2 imaginary solutions

d = b^2 - 4ac

For this problem, the coefficients are:
a = 1, b = -3, c = 8

d = (-3)^2 - 4(1)(8)

d = 9 -32 = -23

d is less than 0, therefore there are 0 real solutions and 2 imaginary solutions.

This is true because you cannot take square root of a negative number.



5 0
3 years ago
The Baltimore Aquarium requires 3 adult chaperones for every 15 students on a field trip. How many chaperones would be needed fo
Elden [556K]
There would need to be 25 adult chaperones. 

The ratio would be 3 adults to every 15 kids. 3:15
To find how many adults are needed for 125 kids you would simply divide.
125/5=25

Hope this helps! :)
6 0
3 years ago
Distance between riverside and milton if they are 12 cm apart on a map with a scale of 4cm : 21 (?
solniwko [45]
You dont have anything that we can answer to.
7 0
3 years ago
For which values of the parameter B the following system admits a unique solution [ 1 b 1-b 2 2 0 2–2B 4 0] [x y z] = [1 2 0]
photoshop1234 [79]

Answer: β ≠ ±1

Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,

det \left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right] ≠ 0

Determinant of a 3x3 matrix is calculated by:

det \left[\begin{array}{ccc}1&\beta&1-\beta\\2&2&0\\2-2\beta&4&0\end{array}\right]\left[\begin{array}{ccc}1&\beta\\2&2\\2-2\beta&4\end{array}\right]

8(1-\beta)-[2(2-2\beta)(1-\beta)]

8-8\beta-4+8\beta-4\beta^{2}

-4\beta^{2}+4\neq 0

\beta^{2}\neq 1

\beta \neq \sqrt{1}

β ≠ ±1

For the system to have only one solution, β ≠ 1 or β ≠ -1.

7 0
3 years ago
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