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2 years ago

Ted is saving for a toy. He has no money now, but

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

6 0

Answer:

4D - 1

Step-by-step explanation:

So, if Ted saves $D for 4 weeks, then this amount will be equal to 4D because multiplication is simply repeated addition. We can imagine this situation as D+D+D+D, for the 4 weeks he is saving. We can simplify this to 4D in the expression.

Next, the question tells us that this will be 1 dollar more than needed. So, if we want to find the cost, we need to subtract that dollar.

Thus, the final expression is 4D - 1 because this represents 1 dollar less than the money he saves for 4 weeks.

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Plz help ASAP I don’t know just tell me the Awnser plz ASAP

Ann [662]

Answer:

The experimental probability is 1/6

Step-by-step explanation:

WIN = 8/48

= 1/6 or 0.1667 = 16.67% chance of winning

LOSE = 40/48

= 5/6 or 0.8333 = 83.33% chance of losing.

I hope this helps. ;)

5 0

3 years ago

James bike 5.40 miles Fred bike 9.2 how much farther did James ride then Fred in a fraction

olga55 [171]

3 8/10 of a mile. You subtract 5.4 from 9.2 and get 3.8 and 3.8 in fraction form is 3 and 8/10. 3 8/10 simplyfied is 3 4/5

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%282%20%5Csqrt%7B3%20%2B%203%20%5Csqrt%7B2%29%20%7B%3F%7D%5E%7B2%7D%20%7D%20%7D%20" id="TexFor

AlladinOne [14]

Answer:

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})$

Step-by-step explanation:

Considering the radical expression

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n$

$=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]$

Simplifying

$\left(\sqrt{3+3\sqrt{2}}\right)^2$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}$

$=\left(\left(3+3\sqrt{2}\right)^{\frac{1}{2}}\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}$

$=\left(3+3\sqrt{2}\right)^{\frac{1}{2}\cdot \:2}$

$=3+3\sqrt{2}$ As $\frac{1}{2}\cdot \:2=1$

So, putting $3+3\sqrt{2}$ into Equation [A]

$=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]$

$\left(\sqrt{3+3\sqrt{2}}\right)^2=3+3\sqrt{2}$

So, Equation [A] becomes

$=2^{2}(3+3\sqrt{2})$

$=4(3+3\sqrt{2})$

Therefore,

$\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})$

Keywords: radical expression

Learn more radical expression from brainly.com/question/11624221

#learnwithBrainly

3 0

3 years ago

The sum of 6 consecutive odd numbers is 204. What is the fourth number in this sequence?

stiv31 [10]

Answer:

Step-by-step explanation:

1. Set up a equation.

2. X is the first, so the ones after x are x+2, x+4, x+6, x+8, and x+10.

3. That means that x+x+2+x+4+x+6+x+8+x+10=204.

4. Simplify. You would get that 6x+30=204.

5. Solve for x. 6x=174, so x=29.

6. Get the fourth number in the sequence. 29+6=35.

Answer: The fourth number in this sequence is 35.

3 0

3 years ago

5x - 3

valentina_108 [34]

PQ is bisected by line <em>L</em>.

so the answer is C

PQ=14

Step-by-step explanation:

5x-3=11-2x

5x+2x=11+3

7x=14

x=2

replace X in any of the given distance equation then multiply by 2 since the distance Pm=Qm

PQ=2(11-2x)

2(11-2(2))

2(7)

Therefore PQ=14

5 0

3 years ago