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3 years ago

Please help me one this someone please!!!

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

90 - x = 4x
4x + x = 90
5x = 90
x = 90/5
x = 18

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Isosceles trapezoid ABCD is shown below with a line EF drawn through its center. If the isosceles trapezoid is dilated using a s

Rus_ich [418]

Answer:

EF will contain the same points. When ABCD is dilated the points EF will stay on the line segments AB and CD.

Step-by-step explanation:

When the figure, ABCD, is dilated, the points EF will remain on the figure. I just had this question a few minutes ago.

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3 years ago

Margie's car can go 32 miles on a gallon of gas, and gas currently costs $4 per gallon. How many miles can Margie drive on $20 w

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160 miles on 20 dollars of gas.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

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3 years ago