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2 years ago

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Min works in the kitchen of a catering company. Today her job is to cut whole pita bread into small triangles. Min uses a cuttin

g machine,so every pita triangle comes out the same. The figure shows an
example. Min has been told to cut 3 pita triangles for every guest. There will be 250 guests. If the pita bread she uses comes in
squares with 20-centimeter sides and she doesn't waste any bread, how many squares of whole pita bread will Min have to cut up?

1 answer:

Ilia_Sergeevich [38]2 years ago

3 0

The number of squares of whole pita bread Min will have to cut up is;

<u><em>21 squares of whole pita bread</em></u>

Since the triangle is isosceles, and has base of 4 cm with 2 equal sides of 6 cm, it means the height is 5.7 cm.

Thus, area of triangle is;

A = ¹/₂ × 4 × 5.7

A = 11.4 cm²

She will cut 3 pita triangles for every guest. This means that;

Area for each guest = 3 × 11.4 = 33.2 cm²

There are 250 guests and so the total needed for the 250 guests is;

Total area = 250 × 33.2

Total area of pita bread = 8300 cm²

The bread comes in 20 cm sides of a square shape.

Area of square = 20 × 20 = 400 cm²

Number of squares of whole pita bread she will have to cut = 8300/400

⇒ 20.75 ≈ 21 squares of whole pita bread

Read more at; brainly.com/question/12973817

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LenaWriter [7]

Simplifying
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Reorder the terms:
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6 + x = -14 + 3x

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Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
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Combine like terms: x + -3x = -2x
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Combine like terms: 3x + -3x = 0
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Add '-6' to each side of the equation.
6 + -6 + -2x = -14 + -6

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Combine like terms: -14 + -6 = -20
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6 0

3 years ago

Read 2 more answers

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

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a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

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Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

3 years ago

HELP PLZ!!!!!!!!!!!!!!!

Andru [333]

B is correct ..............

7 0

3 years ago

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PLEASE HELP?! IM SO CONFUSED!!

seropon [69]

Answer:

C.

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2 years ago

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chubhunter [2.5K]

Hey there!
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x values: -1, 0, 1, 2

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Let's try the third one:

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Always remember: Knowledge is power!

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