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2 years ago

. When should measures of location and dispersion be computed from grouped data

Mathematics

1 answer:

I am Lyosha [343]2 years ago

6 0

Only when individual data values are not available.

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Carlos wrote three numbers between 0.33 and 0.34 what numbers could Carlos have written?

sergij07 [2.7K]

the correct answer is:

Carlos could have written 0.333, 0.334, and 0.3335.

side notes:

hope this helps or is correct!

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3 years ago

What is the probability of rolling a number greater than or equal to 8 with the sum of two dice, given that at least one of the

amid [387]

Answer:

a dice goes from 1-6

6+1=7

6+2=8

6+3=9

6+4=10

6+5=11

6+6=12

Of those possible choices, 5 are greater than or equal to 8. So the answer is 5/6.

mark brainiest please

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3 years ago

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Write an algebraic expression for the phrase the product of 4 and s.

notka56 [123]

Answer: 4s

Step-by-step explanation:

Product means multiply

4 times s = 4s

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3 years ago

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Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund

ser-zykov [4K]

Testing the hypothesis, it is found that since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

$H_0: p = 0.5$

At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

$H_1: p \neq 0.5$

The test statistic is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.
p is the value tested at the null hypothesis.
n is the sample size.

In this problem, the parameters are given by:

$p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482$

The value of the test statistic is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

$z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}$

$z = 2.86$

Since we have a two-tailed test(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

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3 years ago

Help please don’t answer if you don’t know also I’ll give brainliest

egoroff_w [7]

Answer:

10x=4

x=4/10

x=2/5

Step-by-step explanation:

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3 years ago

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