5x3-4x2-20x+16=0 Three solutions were found : x = 4/5 = 0.800 x = 2 x = -2Reformatting the input :Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 1 more similar replacement(s).
Step by step solution :Step 1 :Equation at the end of step 1 : (((5 • (x3)) - 22x2) - 20x) + 16 = 0 Step 2 :Equation at the end of step 2 : ((5x3 - 22x2) - 20x) + 16 = 0 Step 3 :Checking for a perfect cube : 3.1 5x3-4x2-20x+16 is not a perfect cube
Trying to factor by pulling out : 3.2 Factoring: 5x3-4x2-20x+16
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x3+16 Group 2: -4x2-20x
Pull out from each group separately :
Group 1: (5x3+16) • (1)Group 2: (x+5) • (-4x)
I hope it helps
Answer:
a
Step-by-step explanation:
![\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B144a%5E%7B12%7Db%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B4%5D%7B4%5E%7B2%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D%5C%5C%3D%20%5Csqrt%5B4%5D%7B2%5E%7B4%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B3%5E%7B2%7Db%5E%7B3%7D%7D%20%3D%5C%5C%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B9b%5E%7B3%7D%7D)
Answer:
C. quadratic function; quadratic term: −6x^2; linear term: −17x; constant term: −12
Step-by-step explanation:
Answer:
quadratic function; quadratic term: −6x² ; linear term: −17x; constant term: −12
Step-by-step explanation:
The given function is
We need to expand the RHS to get:
We can see that the degree of this polynomial function is 2 and hence it is a quadratic function.
The quadratic term is -6x²
The linear term is -17x
The constant term is -12
Answer:
29
Step-by-step explanation:
-18 (Negative Eighteen) = A
29 (Positive Twenty Nine) = B
11 (Positive Eleven) = C
First, make A positive, and add C to it. You get B.
Now here is the equation:
-18 + (18 + 11)
-18 + (29)
11
