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1 year ago

Please help me wit dis rq

Mathematics

2 answers:

Sonja [21]1 year ago

7 0

I think is you just need to multiply that input number just to get the right answers
Example: 5 multiply by 5 equal 25
Try it

sveticcg [70]1 year ago

3 0

The rule is x 5
if u multiply 5 by each of the input you get the right output

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part b is: if the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading

kotegsom [21]

You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.

Eo = 10^4.4 Joules

E = 2 * 10^15

Formula

M = (2/3) log (E/Eo)

M = 2/3 * log (2 * 10^15/10^(4.4) )

M = 2/3 * log( 7.9621* 10^10)

M = 2/3 * 10.901

M = 7.26735 on the Richter scale. That is a huge amount of energy.

Part B

Suppose that you use Eo and your base. Eo is 10^4.4

Now the new earthquake is E = 10000 * Eo

So what you get now is M = (2/3)* Log(10000 * Eo / Eo )

The Eo's cancel out.

M = 2/3 * log(10000)

M = 2/3 of 4

M = 8/3

M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.

What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667

Answer: M = 2.6667

8 0

3 years ago

Read 2 more answers

Ms. Houston's fifth grade class is going to A museum the class raises $68 for the trip transportation to the museum cost $40The

damaskus [11]

68-40=28
28/4=7
therefore, 7 is your answer
(Hope it helps my friend ^_^)

8 0

3 years ago

Read 2 more answers

Are these parallelograms congruent? 4 cm 6 cm 6 cm 9 cm yes no

lianna [129]

Answer:

Step-by-step explanation:

Yes 6 over 9 simplifys to 2 over 3.

And 4 over 6 simplifys down to 2 over 3

Can I have brainliest please :D

7 0

3 years ago

The value of a car reduces by 30% every 6 months. A car costs $15,000 when new. What is the value of the car after 2 years?

Allisa [31]

6 months goes into 2 years 4 times
30 x 4 = 120
120% of 15,000 is
100% is 1,500
10% is 150
150 x 2 = 300 (20%)
1,500+300=1,800
15,000+1,800=16,800
hope this helped

3 0

3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago