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kakasveta [241]
2 years ago
13

Part One: Find SURFACE AREA. Show your calculations for each face.

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
3 0

Answer:

Step-by-step explanation:

For Part A:

Surface Area = πr(r+ \sqrt{h^{2} + r^{2}  } )

Surface Area = π 3 ( 3 + \sqrt{16 + 9} )

Surface Area = π * 3 (8)

Surface Area = π * 24

Surface Area =75.4

For Part B

V = πr^2 h/3

V = π * 9 * 4/3

v= 37.7

Send love:333

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What are the first five terms, a1, a2, a3, a4, a5 of the sequence defined by an= n^2-9/ n^3 and how can the sequence be describe
Valentin [98]

The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

<h3>Recursive form of a sequence</h3>

Given the nth term of a sequence expressed as:

an= n^2-9/ n^3

Determine the first five terms

If n = 1

a1 = 1^2-9/ 1^3

a1 = -8/1

a1 = -8

If n = 2

a2 = 2^2-9/ 2^3

a2 = -5/8

If n = 3

a3= 3^2-9/ 1^3

a3 = 9-9/3^3

a3 = 0

If n = 4

a4 = 4^2-9/ 4^3

a4= 16-9/64

a4 = 5/64

If n = 5

a5 = 5^2-9/ 1^3

a5 = 25-9/5^3

a5 = 16/125

Hence the first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

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Find the x will name brainlist
Alenkasestr [34]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Find x.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².

Here,

  • Altitude = 1.6 cm.
  • Base = 1.2 cm
  • Hypotenuse = x

Now, let's solve for x.

Hypotenuse² = Base² + Altitude²

x² = (1.2)² + (1.6)²

x² = 1.44 + 2.56

x² = 4

x = √4

x = <em><u>2</u></em><em><u>.</u></em>

  • So, the value of x is <em><u>2</u><u> </u><u>cm.</u></em>

<h3><u>NOTE</u><u> </u><u>:</u><u>-</u></h3>
  • Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
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A manufacturer of piston rings for automobile engines frequently tests the width of the rings for quality control. Last week, a
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Answer:

a) 74.0353 < u <  74.0367

b) 74.036 < u

Step-by-step explanation:

Given:

- Sample size n = 15

- Standard deviation s.d = 0.0001 in

- Sample mean x_bar = 74.036

Find:

A) Calculate the 99% two-sided confidence interval on the true mean piston diameter.

Solution:

- For 99% CI, We have a = 0.01 , and Z_a/2 = 2.58

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u <  (x_bar + Z_a/2*s.d / sqrt(n))

------> (74.036 - 2.58*0.0001 / sqrt(15)) < u <  (74.036 + 2.58*0.0001 / sqrt(15))

------>                               74.0353 < u <  74.0367

Find:

B) Calculate the 95% one-sided lower confidence interval on the true mean piston diameter.

Solution:

- For 95% lower CI, We have a = 0.05 , and Z_a = 1.645

------> (x_bar - Z_a/2*s.d / sqrt(n)) < u

------> (74.036 - 1.645*0.0001 / sqrt(15)) < u

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