Simple...
you have: 6a+3b-8
a=4 and b=5
Plug in what you know-->>
6(4)+3(5)-8
24+15-8
39-8
31
Thus, your answer.
Answer:
n >_ 4
Step-by-step explanation:
move 9 to the other side
n >_ 13 - 9
n >_ 4
Answer:

Step-by-step explanation:
Given the expression




Cancel the common factor: x+y

Thus,

Answer:
Step-by-step explanation:
Given that there is a polar equation as

This has to be converted into cartesian.
We know the conversion is

Using this we can say that

}
Circle with centre (0,6) and radius 6.
3.579 is greater.
It is relatively closer to 4 than the other number. 3 and 3 are equal, 5 and 5 are equal, but 7 is greater than 6. Hope this helps :)