Answer:

Step-by-step explanation:
<u>Find the measures of interior angles in each triangle</u>
Triangle BGC

The measures of triangle BGC are 
Triangle CGH
we know that
-----> by consecutive interior angles
we have that
so

substitute

we have



remember that




The measures of triangle CGH are 
Triangle GHE


remember that

substitute and solve for m<GEH



The measures of triangle GHE are 
<h3>
Answer: 140625 </h3>
======================================================
Explanation:
Replace every copy of "w" with "x"
So the function we graph is y = (1500-2x)*x/2
I used GeoGebra to make the graph below. Note the scale on the xy axis. In this case, x is incrementing by 100 while y is incrementing by 50,000. The scale is important so you have a good viewing window. You don't have to have this scale exactly, but something close to it should do the trick. Without the proper scale, you probably won't see the curve at all. You may see a straight line instead, or it may appear completely blank.
You can use Desmos to make the graph. Just keep in mind the scale of course.
Once you have the graph set up, use the max feature of your graphing calculator or graphing software to locate the vertex point. In GeoGebra, the function I used is "Max". I typed in Max(f, 0, 800) where f is the function mentioned earlier. With Desmos, you simply need to click on the curve itself to have the max point show up. Click on the vertex point to have the coordinates listed.
The max point is located at A = (375, 140625) as shown in the diagram below. The x coordinate is the value of "w" that we replaced earlier. So a width of w = 375 feet corresponds to the max area of 140625 square feet.
Side note: later on in your math career, you have the option to use calculus to solve a problem like this. Though for now, we can rely on a graphing calculator to get the job done quickly.
-x^2+4x-4
dy/dx=-2x+4, d2y/dx2=-2
Since acceleration is a constant negative, when dy/dx, velocity, equals zero, it is at the absolute maximum value for f(x).
dy/dx=0 when -2x+4=0, 2x=4, x=2
f(2)=-x^2+4x-4=-4+8-4=0
So there is a maximum of zero
...
.5x^2+8x+5
dy/dx=x+8, d2y/dx2=1
Since d2y/dx2, acceleration is a constant positive, when dy/dx=0, it is at the point when f(x) is at an absolute minimum.
dy/dx=0 when x+8=0, x=-8
f(-8)=.5x^2+8x+5=32-64+5=-27
So there is a absolute minimum of -27
...
-2(x+1)^2+5
dy/dx=-4(x+1)=-4x-4, d2y/dx2=-4
dy/dx=9 when -4x-4=0, -4x=4, x=-1
f(-1)=5
So the vertex is (-1, 5) and the axis of symmetry is the vertical line x=-1
Answer:
A
Step-by-step explanation:
use the equation y-1=m(x-x1)
the slope is the same as the m which is the gradient
x1 is 5 and y1 is 2.the x and the y are constants
replace the values given in the equation
y-2=3(x-5)
y-2=3x-15
y=3x-13
I hope this helps