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3 years ago

For f(x) = 3x - 5 and g(x) = x2 + 2, find (f+ g(x).

Mathematics

1 answer:

Vladimir [108]3 years ago

8 0

Answer:

Step-by-step explanation:

hello :

f(x) = 3x - 5 and g(x) = x² + 2

(f+ g)(x)= f(x)+g(x) = 3x-5 +x²+2

(f+ g)(x).= x²+3x-3

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Diano4ka-milaya [45]

Answer:

which class question is this

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3 years ago

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is

$P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1$

$P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4$

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

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3 years ago

−4x−y=24minus, 4, x, minus, y, equals, 24Complete the missing value in the solution to the equation.

Serggg [28]

Answer:

there is no solution to the problem but after calculating and searching a possible answer is

x = -6

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Step-by-step explanation:

4 0

3 years ago

A town's population went from 25,800 to 42,600 in 15 years. What was the percent of changes?

melomori [17]

42,600 - 25,800 = 16800. That is the increase in 15 years.

You then calculate the increase as a percentage of the original population; 25,800.

16,800 / 25,800 * 100 = 65.11%

8 0

3 years ago

What is the formula for a confidence interval?

ikadub [295]

Answer:

a) The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

b) $\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

5 0

3 years ago