Question

What is the solution for the equation startfraction 5 over 3 b cubed minus 2 b squared minus 5 endfraction = startfraction 2 over b cubed minus 2 endfraction? b = –4 and b = 0 b = –4 b = 0 and b = 4 b = 4

Answer 1

Answer:

c

Step-by-step explanation:

Answer 2

An equation is formed of two equal expressions. The solution of the equation is 4.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution of the equation can be written as,

$\dfrac{5}{3b^3-2b^2-5} = \dfrac{2}{b^3-2}\\\\5(b^3-2) = 2(3b^3-2b^2-5)\\\\5b^3-10=6b^3-4b^2-10\\\\5b^3-10-6b^3+4b^2+10=0\\\\-b^3+4b^2=0\\\\b^2(-b+4)=0\\\\-b+4=0\\\\-b=-4\\\\b=4$

Thus, the solution of the equation is 4.

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