<span>fourth degree polynomial with three terms
the degree is the highest exponent the term are separated by plus or minus </span>
Answer:
-3, 1, 4 are the x-intercepts
Step-by-step explanation:
The remainder theorem tells you that dividing a polynomial f(x) by (x-a) will result in a remainder that is the value of f(a). That remainder will be zero when (x-a) is a factor of f(x).
In terms of finding x-intercepts, this means we can reduce the degree of the polynomial by factoring out the factor (x-a) we found when we find a value of "a" that makes f(a) = 0.
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For the given polynomial, we notice that the sum of the coefficients is zero:
1 -2 -11 +12 = 0
This means that x=1 is a zero of the polynomial, and we have found the first x-intercept point we can plot on the given number line.
Using synthetic division to find the quotient (and remainder) from division by (x-1), we see that ...
f(x) = (x -1)(x² -x -12)
We know a couple of factors of 12 that differ by 1 are 3 and 4, so we suspect the quadratic factor above can be factored to give ...
f(x) = (x -1)(x -4)(x +3)
Synthetic division confirms that the remainder from division by (x -4) is zero, so x=4 is another x-intercept. The result of the synthetic division confirms that x=-3 is the remaining x-intercept.
The x-intercepts of f(x) are -3, 1, 4. These are the points you want to plot on your number line.
So right now you see that you have x and y intercept right? Then plug those intercepts in equation that you have and solve for z. Which means z=5(1)(1) will be 5, 5(4)(1) will be 20, and 5(1)(2) will be 10. So, overall you have 5, 20, 10.
SOLUTION
We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).
In P(-5,1), x = -5 and y = 1
In Q(-4,6), x = -4 and y = 6 and
In R(-2,3), x = -2 and y = 3

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.