The answer is 12. This is the step by step
Notice how 2^2 = 4 is one short of 5, so this means we can say 4/5 = 0 remainder 4 or we can write that "remainder 4" as "remainder -1" to say the same basic thing
Using modulus arithmetic, we can say...
2^2 = 4 = -1 (mod 5)
(2^2)^31 = (-1)^31 = -1 (mod 5)
2*(2^2)^31 = 2*(-1) (mod 5)
2^63 = -2 = 3 (mod 5)
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So the remainder of 2^63 divided by 5 is the value 3
Answer: 3
Answer: I’ll give you an example of how to do it by solving number 9 - h^2 + 8h + 16
Step-by-step explanation:
Step 1: Find two numbers that when you multiply them it gives you the first term’s coefficient multiplied by the last term’s coefficient (1x16 = 16) and when you add them it gives you the second term’s coefficient (8). The numbers in this case are positive 4 and positive 4.
Step 2: Create two parenthesis with the letter accompanied by the numbers. (h + 4)•(h+4). And that’s how you factor.
In case the first term is elevated to the third you will have to take out GCF (greatest common factor) first. If the numbers are too high like in the exercise number 15 you can also take out GCF and it will make it a lot easier to solve. Sometimes what you write on the parenthesis in the step 2 can be simplified, if that’s so then you would have to do it in order to get the correct answer.
Hope this helps you.
Suppose that X is a vertical segment that lies on the y-axis with its beginning at origin and ending at the point (0,4). Then the length of this segment is 4 units.
If you vertically compress this segment by factor of 1/4 with the centre of compression at the origin, you recieve a segment that also lies on the y-axis with its beginning at origin and ending at the point (0,1) (the length of this image segment is 1 unit).
So, the question is: if a segment that lies on the y-axis with its beginning at origin and ending at the point (0,4) is vertically compressed <span>by factor of 1/4 with the centre of compression at the origin, what is the image of this transformation?
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Answer:
5600*.065=364
5600+364=$5964 in the account at the end of the year. ☺☺☺☺