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Agata [3.3K]
3 years ago
8

I need help with converting liters, millilters, kiloliters etc? Okay, i am really confused! I don't understand how to get 75.01

liters into milliters. I don't understand how to get 367,000 milliliters into kiloliters. I really need help understanding the process of how to do it!? Thanks if you can help me. :)

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0
Firstly, understand prefixes :)

giga 1000000000
mega 1000000
kilo 1000
deci 0.1
centi 0.01
milli 0.001
micro 0.000001
nano 0.000000001

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Given that the measure of ∠x is 60°, and the measure of ∠y is 110°, find the measure of ∠z.
Nitella [24]

Answer:

<h2>∠z = 10°</h2>

Step-by-step explanation:

A triangle is always 180 degrees.

If ∠x is 60°

and ∠y is 110°,

110 + 60 = 170

∠z = 10 degrees

6 0
3 years ago
Dylan wants to buy both the tablet and
nignag [31]

Answer:

108$

Step-by-step explanation:

6 0
3 years ago
Use the perfect square method <br> (3x + 3)^2 = 36
kkurt [141]

Factor out the common term; 3

(3(x + 1))^2 = 36

Use the Multiplication Distributive Property; (xy)^a = x^ay^a

3^2(x + 1)^2 = 36

Simplify 3^2 to 9

9(x + 1)^2 = 36

Divide both sides by 9

(x + 1)^2 = 36/9

Simplify 36/9 to 4

(x + 1)^2 = 4

Take the square root of both sides

x + 1 = √4

Since 2 * 2 = 4, the square root of 2 is 2

x + 1 = 2

Break down the problem into these 2 equations

x + 1 = 2

x + 1 = -2

Solve the first equation; x + 1 = 2

x = 1

Solve the second equation; x + 1 = -2

x = -3

Collect all solutions;

<u>x = 1, -3</u>

8 0
3 years ago
A thermometer is taken from a room where the temperature is 24oc to the outdoors, where the temperature is −15oc. After one minu
kap26 [50]

Solution:

Use Newton's Law of Cooling.  


T = T_s + (T_0 - T_s)*e^(-kt)  


where  

T = temperature at any instant  

T_s = temperature of surroundings  

T_0 = original temperature  

t = elapsed time  

k = constant  


Now, we need to find this constant. We are given that after one hour, the temperature drops to 13° C in a 7°C Environment.  

T = 14, T_0 = 24, T_s = -15, t = 1, k = ?  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> 14 = -15 + (24 - 7)*e^(-k)  

==> 14 = 7 + 17*e^(-k)  

==> 7 = 17*e^(-k)  

==> 7/13 = e^(-k)  

==> -k = ln(7/17)  

==> k = -ln(7/17) ≈ 0.774  

Now,


Let's calculate temperatures!  

T = ?, T_0 = 24, T_s = -15, k = 0.773, t = 3  

T = T_s + (T_0 - T_s)*e^(-kt)  

==> T = -15 + (24 –(-15))*e^[ -(0.774)(2) ]  

==> T = -15 + 39*e^(-1.548)  

==> T ≈ 15.72° C  

This the required answer.


7 0
3 years ago
What is the sign of 3x y3xy3, x, y when x&gt;0x&gt;0x, is greater than, 0 and y&lt;0y&lt;0y, is less than, 0?
jekas [21]

Answer:

Negative

Step-by-step explanation:

We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y

4 0
4 years ago
Read 2 more answers
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