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xxMikexx [17]
3 years ago
15

If cost of 15 eggs is Rs. 75, then find out the cost of 4 dozens eggs.

Mathematics
1 answer:
attashe74 [19]3 years ago
4 0

Answer:

The answer is d 240. You will first find how much 1 egg costs then times 12 times 4 equal to 48 times how much 1 egg Costs equal to 240

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Alenkinab [10]

Given:

\sigma_A=3

n_A=6

\sigma_B=5

n_B=4

\overline{x}_A=\overline{x}_B

To find:

The variance. of combined set.

Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

54=\sum (x_i-\overline{x}_A)^2

Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

100=\sum (x_i-\overline{x}_B)^2

Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

\sigma^2=\dfrac{54+100}{6+4}

\sigma^2=\dfrac{154}{10}

\sigma^2=15.4

Therefore, the variance of combined set is 15.4.

7 0
3 years ago
5/12 greater than 1/4
katrin [286]
1/4 = 3/12

3/12 < 5/12

Therefore, 5/12 is greater than 1/4
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Answer:

\frac{10}{23}

Step-by-step explanation:

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saveliy_v [14]

Answer:

A

Step-by-step explanation:

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