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liq [111]
3 years ago
8

I dont know how to do this please help and also please explain, thank you:)​

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

it's A lol

.................................

Stells [14]3 years ago
8 0

Answer: 284/1000

Step-by-step explanation:

if you look at it like this:

when you have .2, that would equal 2/10 because its 2 tenths

when you have .28 that would equal 28/100 or 28 hundreths since it is greater than 2 tenths

that means with this, it would be .284 or 284/1000 or 284 thousandths because it is larger than both hundreths and tenths.

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What is the value of 780/60
a_sh-v [17]

Answer: 13

Step-by-step explanation: If you add 13 to itself 60 times, you will get 780.

5 0
1 year ago
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At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017
Anarel [89]

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

4 0
3 years ago
Find the inverse of the following matrix without using a calculator 1-1 2 -3 2 1 0 4 - 25
Artist 52 [7]

Answer:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

Step-by-step explanation:

You can solve this problem by using the Gauss-Jordan method.

You have the original matrix and then the Identity matrix.

So:

Original              Identity

1 -1 2                    1 0 0

-3 2 1                   0 1 0

0 4 -25                0 0 1

By the Gauss-Jordan method, in the original place you will have the identity and in the place that the identity currently is you will have the inverse matrix:

So, let's start by setting the first row element to 0 in the second and the third line.

The first row element of the third line is already at zero, so no changes there. In the second line, we need to do:

L2 = L2 + 3L1

So now we have the following matrixes.

1 -1 2        |            1 0 0

0 -1 7       |            3 1 0        

0  4 -25   |            0 0 1

Now we need the element in the second line, second row to be 1. So we do:

L2 = -L2

1 -1 2        |            1 0 0

0 1 -7       |            -3 -1 0        

0  4 -25   |            0 0 1

Now, in the second row, we need to make the elements at the first and third line being zero. So, we have the following operations:

L1 = L1 + L2

L3 = L3 - 4L2

Now our matrixes are:

1 0 -5       |            -2 -1 0

0 1 -7       |            -3 -1 0        

0 0 3       |            12 4 1

Now we need the element in the third line, third row being one. So we do:

L3 = -L3

1 0 -5       |            -2  -1     0

0 1 -7       |            -3  -1      0        

0 0 1       |            4    (4/3) (1/3)

Now, in the third row, we need the elements in the first and second line being zero. So we do:

L1 = L1 + 5L3

L2 = L2 + 7L3

So we have:

1 0 0 |       18  -(17/3)   (5/3)

0 1 0 |       25  (25/3)  (7/3)

0 0 1 |       4    (4/3)     (1/3)

So the inverse matrix is:

18  -(17/3)   (5/3)

25  (25/3)  (7/3)

4    (4/3)     (1/3)

4 0
3 years ago
Which of the following is not a correct description of the graph of the function y = -2x - 7?
swat32
The graph of the function contains the points (0,-7), (1,-9), and (3,-1) is incorrect

it contains all the points except the last set...(3,-1)
y = -2x - 7
-1 = -2(3) - 7
-1 = -6-7
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3 years ago
Rectangle, Square, or Rhombus?
saveliy_v [14]

Answer:

maybe rhombus

Step-by-step explanation:

don't take my word for it

4 0
2 years ago
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