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liq [111]
3 years ago
8

I dont know how to do this please help and also please explain, thank you:)​

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

it's A lol

.................................

Stells [14]3 years ago
8 0

Answer: 284/1000

Step-by-step explanation:

if you look at it like this:

when you have .2, that would equal 2/10 because its 2 tenths

when you have .28 that would equal 28/100 or 28 hundreths since it is greater than 2 tenths

that means with this, it would be .284 or 284/1000 or 284 thousandths because it is larger than both hundreths and tenths.

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Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
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Simplify (use only positive exponents) : (3y^10)(2y^2)/8y^5
nadezda [96]
When multiplying variables with exponents, all you have to do is to add the exponents and that’s the ‘product.’

So;

(3y^10)(2y^2) is equal to (3)(2)(y^10+2).

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When dividing exponents, you do the opposite and subtract the exponents. And you divide the whole number by half.


6y^12/8y^5 = 3y^7/4

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Answer:

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Step-by-step explanation:

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Beth has 144 inches of ribbon.
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