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liq [111]
3 years ago
8

I dont know how to do this please help and also please explain, thank you:)​

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

it's A lol

.................................

Stells [14]3 years ago
8 0

Answer: 284/1000

Step-by-step explanation:

if you look at it like this:

when you have .2, that would equal 2/10 because its 2 tenths

when you have .28 that would equal 28/100 or 28 hundreths since it is greater than 2 tenths

that means with this, it would be .284 or 284/1000 or 284 thousandths because it is larger than both hundreths and tenths.

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Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope
Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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  • z is the critical value.
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In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

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\pi = \frac{179}{523} = 0.3423

Then the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago
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4•|11|+3
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