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Gwar [14]
2 years ago
10

Expand (2x+ 3)² Please guys​

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
3 0

Answer:

4x^2 + 12x + 9.

Step-by-step explanation:

(2x+3)^2

= (2x+3)(2x+3)

= 2x(2x+3)+3(2x+3)

= 4x^2 + 6x + 6x + 9

= 4x^2 + 12x + 9.

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Which car can travel at the slowest rate? Plz help fast
grigory [225]

Answer:

D


Step-by-step explanation:

Let's find unit rate of each (number of miles traveled in 1 hour). For that we will divide the distance by time to get the unit rate.

Note: rate=\frac{Distance}{Time}


(A)

rate = \frac{300}{4}=75 mph (miles per hour)

(B)

rate = \frac{450}{6}=75 mph

(C)

rate = \frac{750}{10}=75 mph

(D)

rate = \frac{800}{12}=66\frac{2}{3} mph


<u>As we can see, the first 3 rates are same, 75 mph, and the last one is 66\frac{2}{3} mph. So clearly, the last rate is the slowest.</u>

D is the right answer.

7 0
2 years ago
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11/10= x+2/5 Please Explain
luda_lava [24]

Answer:

x=7/10

Step-by-step explanation:

2/5=4/10

11/10=x+4/10

11/10-4/10=x

7/10=x

4 0
3 years ago
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The inequality 6-2/3x
densk [106]

Answer:

ask a teacher

Step-by-step explanation:

5 0
3 years ago
Free brainiest and 100 point so first person to answer what's 3+3
Natasha_Volkova [10]

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2 years ago
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A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line
natulia [17]

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker

so

\frac{x}{1} =\frac{205}{5}

cross multiply

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41 calories in 1 cracker

Number line:

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2 years ago
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