1. How many ways are there to make an octagon with 19 different sticks when order DOESN’T matter?

Mathematics

1 answer:

mart [117]3 years ago

6 0

Answer:

1. 19C8 = 75582

2. 19P8= 3047466240

Step-by-step explanation:

First, find the number of ways to get 8 sticks from 19. At first, you have 19 choices, then 18, then 17, all the way to 12. Giving you 19*18*17*...*13*12, or 19!/11!.

Combination:

When order doesn't matter, you have to divide 19!/11! by the number of ways to order 8 sides, or 19!/11!/8!=19C8=75582

Permutation:

When order doesn't matter, you don't have to divide 19!/11! by the number of ways to order 8 sides, since you count each of these, and 19!/11!=19P8=3047466240.

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Neporo4naja [7]

Answer:

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Step-by-step explanation:

Based on the tree diagram we need to tell the the probability that the test for lice returns a false positive. False positive means that the student has no lice but still the test shows a positive result.

So for this we have to first look for the branch, from the starting node, which shows that student has no lice. From the starting point, the upper branch represents the students that have lice and lower branch represents the students who have no lice. So, we will consider the lower branch with probability mentioned as 0.82

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Step-by-step explanation:

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<h3><u><em>Please mark this as brinliest thank you!!!</em></u></h3><h3><u><em>: )</em></u></h3><h3><u><em>And as always, </em></u></h3><h3><u><em>simplify bananas</em></u></h3>

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Answer and Step-by-step explanation:

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