Answer:mean
Step-by-step explanation: I am also not sure because I been looking for the anwser to this but I think it’s mean
Let a, b, and c be the times each pump will fill the tank when working alone.
Therefore, in 1 hour;
1/a +1/b = 1/(6/5) = 5/6 ---- (1)
1/a+1/c = 1/(3/2) = 2/3 ---- (2)
1/b+1/c = 1/(2) = 1/2 ---- (3)
From equation (1)
1/a = 5/6-1/b
Substituting for 1/a in eqn (2)
5/6-1/b+1/c = 2/3
-1/b +1/c = -1/6 => 1/c = 1/b - 1/6 --- (4)
Using eqn (4) in eqn (3)
1/b+1/b-1/6 = 1/2
2/b-1/6 = 1/2
2/b =1/2+1/6 = 2/3
1/b = 1/3
Then,
1/c = 1/3 - 1/6 = 1/6
1/a = 5/6 - 1/3 = 1/2
This means, in 1 hour and with all the pumps working together, the tank will be filled to;
1/a+1/b+1/c = 1/2+1/3+1/6 = 1 (filled fully).
Therefore, it will take 1 hour to fill the tank when all pumps are working together.
The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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I believe that the answer is 3+84x is this question wants you to simplify the expression.