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2 years ago

What is the answer to 3/4 times 6?

Mathematics

1 answer:

puteri [66]2 years ago

6 0

Answer:

4.5 or 4 1/2

Step-by-step explanation:

An easy way to do this problem is to divide 6 by 4, the denominator (1.5) then multiply it by the numerator, 3, which will now be 4.5.

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The graph below shows the cost of pens based on the number of pens in a pack. What would be the cost of one pen

worty [1.4K]

Answer:

$1.25

Step-by-step explanation:

The graph shows that 3 pens cost $3.75 which means each pen costs more than $1 so we know that the greater number will be the numerator in our division equation. Divide 3.75 by 3 to get the unit rate.

3.75/3=1.25

Each pen costs 1.25

You can check your work by plugging it into the other points.

6*1.25=7.5 -So that second point is correct

9*1.25=11.25- The third point is also correct meaning we got the right answer

3 0

3 years ago

John has 6 pairs of pants and 3 shirts. How many possible outfits consisting of one shirt and

Step2247 [10]

Answer:

Step-by-step explanation:

3 shirts for each pants

4 0

3 years ago

Read 2 more answers

Someone help!! 20 points to whoever can help me with this problem and give me the correct reasoning

MrMuchimi

Answer:

Step-by-step explanation:

180-(60+40)=180-60-40=180-100=80

4 0

3 years ago

Read 2 more answers

Subtract the polynomials (−9x2+8x+2)−(4x2+2x−5)

Zielflug [23.3K]

(9 x² + 8 x + 2) - ( 4 x² + 2 x -5 )
= 9 x² + 8 x + 2 - 4 x² - 2 x + 5
= 5 x² + 6 x + 7

4 0

4 years ago

A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv

lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

of novels that seniors read during their time in college. An exit

survey was conducted with a random sample of 9 seniors. The

sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

been met, which of the following is a 94.645% confidence

interval for the population mean number of novels read by

all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

= n - 1

= 9 - 1

= 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

=1 - 0.94645

=0.05355 ≈ 0.05

⇒α = 0.5

Now,

$\frac{\alpha}{2} = \frac{0.05}{2}$

= 0.025

Then,

$t_{\frac{\alpha}{2}, df }$ = 2.306

∴ we get

Population mean = x⁻ ± $t_{\frac{\alpha}{2}, df }$ × $\frac{s}{\sqrt{n} }$

= 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

⇒Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

3 0

4 years ago

Read 2 more answers