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WINSTONCH [101]
3 years ago
10

Someone help!! 20 points to whoever can help me with this problem and give me the correct reasoning

Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Answer:

Angle CAB= 80 Degrees

Step-by-step explanation:

The angle A can be found by taking the sum of angles in the 2 separate triangles and adding them together.

We know that a straight line is 180 degrees. The angle ADC is given to be 90 degrees, therefore angle BDA is also 90 degrees because 180-90=90 degree (congruent angle). (both the small triangles are right angle triangles) This gives us 2 angle measurements in each triangle. This means for both triangkes we can add the 2 angle measurements to find the sum of both andlges and subtract that number from 180 because 180 is the sum of all angles in a triangle.

For Triangle BDA we add angle B (40 degrees) and angle D (90 degrees)

Angle= 180- (40+90)

Angle= 180-130

Angle= 50 degrees

For triangle DAC we add angle D(90 degrees) and angle C(60 degrees)

Angle= 180- (90+60)

Angle = 180-150

Angle= 30 degrees

To find the angle measurement for angle CAB we add the answer from both the calculations as shown above (add 50 and 30)

Angle CAB= 50+30

Angle CAB= 80 degrees

Therefore angle CAB= 80 degrees

MrMuchimi3 years ago
4 0

Answer:

80

Step-by-step explanation:

180-(60+40)=180-60-40=180-100=80

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7(3x + 5y)<br> Simplify this expression please!
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Answer:

21x + 35y

Step-by-step explanation:

Distribute the 7 to everything in the parentheses.

7*3=21

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5 0
3 years ago
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When a figure is translated, what is true, compared to the preimage of the figure
Charra [1.4K]
When you translate something in geometry, you're simply moving it around. You don't distort it in any way. If you translate a segment, it remains a segment, and its length doesn't change. Similarly, if you translate an angle, the measure of the angle doesn't change.
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Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t &gt; 0.
Margarita [4]

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y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

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yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

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= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

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3 0
3 years ago
Messed up and didnt put the attachment on the last post
Margarita [4]

<u>Answer</u><u> </u><u>:</u><u>-</u>

9(3+√3) feet

<u>Step </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u>

A triangle is given to us. In which one angle is 30° and length of one side is 18ft ( hypontenuse) .So here we can use trignometric Ratios to find values of rest sides. Let's lable the figure as ∆ABC .

Now here the other angle will be = (90°-30°)=60° .

<u>In ∆ABC , </u>

=> sin 30 ° = AB / AC

=> 1/2 = AB / 18ft

=> AB = 18ft/2

=> AB = 9ft .

<u>Again</u><u> </u><u>In</u><u> </u><u>∆</u><u> </u><u>ABC</u><u> </u><u>,</u><u> </u>

=> cos 30° = BC / AC

=> √3/2 = BC / 18ft

=> BC = 18 * √3/2 ft

=> BC = 9√3 ft .

Hence the perimeter will be equal to the sum of all sides = ( 18 + 9 + 9√3 ) ft = 27 + 9√3 ft = 9(3+√3) ft .

<h3><u>Hence </u><u>the</u><u> </u><u>perim</u><u>eter</u><u> of</u><u> the</u><u> </u><u>triangular</u><u> </u><u>pathway</u><u> </u><u>shown</u><u> </u><u>is</u><u> </u><u>9</u><u> </u><u>(</u><u> </u><u>3</u><u> </u><u>+</u><u> </u><u>√</u><u>3</u><u> </u><u>)</u><u> </u><u>ft</u><u> </u><u>.</u></h3>
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