![(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \\---------------------------\\ \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}} \\ \quad \\ \textit{we know the center}\implies center\ ({{ 6}},{{ 8}}) \\ \quad \\ \textit{what's the radius "r"?} \\ \quad \\ \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) Center&({{ 6}}\quad ,&{{ 8}})\quad % (c,d) P&({{ 4}}\quad ,&{{ 1}}) \end{array}\qquad % distance value r= \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}](https://tex.z-dn.net/?f=%28x-%7B%7B%20h%7D%7D%29%5E2%2B%28y-%7B%7B%20k%7D%7D%29%5E2%3D%7B%7B%20r%7D%7D%5E2%0A%5C%5C---------------------------%5C%5C%0A%5Cqquad%20center%5C%20%28%7B%7B%20h%7D%7D%2C%7B%7B%20k%7D%7D%29%5Cqquad%0Aradius%3D%7B%7B%20r%7D%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bwe%20know%20the%20center%7D%5Cimplies%20center%5C%20%28%7B%7B%206%7D%7D%2C%7B%7B%208%7D%7D%29%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bwhat%27s%20the%20radius%20%22r%22%3F%7D%0A%5C%5C%20%5Cquad%20%5C%5C%0A%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0ACenter%26%28%7B%7B%206%7D%7D%5Cquad%20%2C%26%7B%7B%208%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AP%26%28%7B%7B%204%7D%7D%5Cquad%20%2C%26%7B%7B%201%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ar%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D)
find "r", then plug it in the circle's equation
Answer:
∠1 = 96°
∠2 = 84°
∠3 = 84°
Step-by-step explanation:
∠1 = 96°
∠2 = ∠3
∠1 + 96 + ∠2 + ∠3 = 360°
∠2 = (360 - 96 - 96)/2 = 84°
∠3 = 84°
1.898 kilograms... as you just have to divide
Answer:
5
10
4
7
Step-by-step explanation:
Apply the value of x into the expressions:
3(5) - 10 = 15 - 10
= 5
5² - 15 = 25 - 15
= 10
5(5) - 21 = 25 - 21
= 4
5 + 10 - 8 = 15 - 8
= 7
Answer:
5% chance
Step-by-step explanation: