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tatiyna
3 years ago
15

For the graphed function f(x) = (2)x + 2 + 1, calculate the average rate of change from x = −1 to x = 0. a graph of an exponenti

al function that goes through the points negative 2 comma 2, negative 1 comma 3, and 0 comma 5 −2 2 3 −3
Mathematics
2 answers:
maxonik [38]3 years ago
6 0

Answer:

2

Step-by-step explanation:

i took it a couple weeks ago and can confirm its right

Paladinen [302]3 years ago
3 0

Answer:

2 is the average rate of change of the function f(x)=2^{x+2}+1 from x=-1 to x=0.

Step-by-step explanation:

I assume you meant f(x)=2^{x+2}+1 based off the points.

We are given that (-1,3) and (0,5) are points on this curve.

We are asked to find the average rate of change (the slope) from x=-1 to x=0.

We have the two points needed to find the slope.

We just need to line them up and subtract vertically then put 2nd difference on top of 1st difference.

(-1,3)

(0,5)

--------------------Subtracting!

-1,-2

So the slope is \frac{-2}{-1}=2.

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i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
Solve each quadratic equation. Show your work.<br><br><br> 14. (2x – 1)(x + 7) = 0
melisa1 [442]
<span>(2x – 1)(x + 7) = 0

2x-1=0
2x=1
x=1/2
x=0.5

x+7=0
x= -7
</span>
5 0
3 years ago
Read 2 more answers
Please help I think these are the right answers!!!
Papessa [141]

We performed the following operations:

f(x)=\sqrt[3]{x}\mapsto g(x)=2\sqrt[3]{x}=2f(x)

If you multiply the parent function by a constant, you get a vertical stretch if the constant is greater than 1, a vertical compression if the constant is between 0 and 1. In this case the constant is 2, so we have a vertical stretch.

g(x)=2\sqrt[3]{x}\mapsto h(x)=-2\sqrt[3]{x}=-g(x)

If you change the sign of a function, you reflect its graph across the x axis.

h(x)=-2\sqrt[3]{x}\mapsto m(x)=-2\sqrt[3]{x}-1=h(x)-1

If you add a constant to a function, you translate its graph vertically. If the constant is positive, you translate upwards, otherwise you translate downwards. In this case, the constant is -1, so you translate 1 unit down.

5 0
3 years ago
What is the value of b in the equation below? 9^-8 x 9^-2 = a^b <br> -10 <br> -6 <br> 9 <br> 16
lys-0071 [83]

Answer:

-10

Step-by-step explanation:

9^-8 x 9^-2 = a^b

We know that x^y * x^z = x^(y+z)

9^-8 x 9^-2 = 9^(-8+-2) = 9^(-10)

a= 9  

b = -10

3 0
3 years ago
Read 2 more answers
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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