<u>Answer:</u>
, 
, 
, 
<u>Step-by-step explanation:</u>
First, we subtract 128 from both sides:
Then, we subtract 
from both sides:
Rewrite the equation:
Insert and solve:
<em>Please give Brainliest</em>
Answer: (x - 4)(x - (i))(x + (i))
Step-by-step explanation:
This factoring job lends itself well to synthetic division. Looking at the constant term, -4, I came up with several possible roots based upon -4: {±1, ±2, ±4}. I chose +4 as my first trial root. Sure enough, there was a zero remainder, which indicated that 4 is a root of this polynomial and (x - 4) is a factor. The coefficients of the trinomial quotients are 1 0 1, which indicates a quotient of x^2 + 1, which has the following roots: x = +(i) and x = -(i)
So the complete factorization of the polynomial is (x - 4)(x - (i))(x + (i)).
4 ) 1 -4 1 -4
----------------------
Answer:
1
These are so easy, you won't believe it !
A negative exponent only means
"Put all of this in the denominator, and make the exponent positive."
So (any number)^negative power =
1 / (the same number)^(the same power but not negative) .
The first few problems on that sheet:
1). 5^-3 = 1 / 5^3
2). 6^-10 = 1 / 6^10
3). (-2)^-5 = 1 / (-2)^5
Got it ? You can do the rest of them now in about 2 minutes.
