2 years ago

I dont know i need help please

Mathematics

1 answer:

Minchanka [31]2 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Algebra help please I have to get it done .

Finger [1]

Its Letter A see photo for solution

3 0

3 years ago

Georgia ran a 5-kilometer race. How many meters did she run?

kumpel [21]

Answer:

Georgia ran 5000 meters

Step-by-step explanation:

1 kilometer = 1000 meter

4 0

3 years ago

Read 2 more answers

What is the slops that passes through (5,6) and (7,10)

Triss [41]

2 is the correct answer I believe

7 0

2 years ago

Read 2 more answers

Simiplify without using absolute value bars, Solve for |x +7| for x>=7

Pavlova-9 [17]

9514 1404 393

Answer:

x +7

Step-by-step explanation:

The argument of the absolute value function is positive for any x > -7. The required domain is a subset of that, so the absolute value function does not change its argument.

|x+7| for x ≥ 7 is x +7

5 0

2 years ago

Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

6 0

2 years ago