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2 years ago

I do not know this answer

Mathematics

1 answer:

Bogdan [553]2 years ago

4 0

Answer:

try (-4,6)

Step-by-step explanation:

if you use tracing paper, put a mark where the point is

put the tip of the pencil on the point which it will rotate around

spin the paper by the degrees

see where the traced point ends up

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A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?

jarptica [38.1K]

Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

<u>Given the following data:</u>

Amplitude = 3

Period = π

Phase shift = π/2

<h3>How to determine the y-intercept of this function?</h3>

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

<u>Where:</u>

A represents the amplitude.

ω represents angular velocity.

t represents the period.

ø represents the phase shift.

Also, the period of a sine wave is given by:

t = 2π/ω

2 = 2π/ω

ω = 2

Substituting the given parameters into the equation, we have;

y = 3sin(2t + π/2)

At t = 0, we have:

y = 3sin(2(0) + π/2)

y = 3sin(π/2)

y = 3sin(90)

y = 3 × 1

y = 3.

In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.

Read more on phase shift here: brainly.com/question/27692212

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5 0

2 years ago

Pam kept track of the puppies available for adoption at the shelter. After 4 hours, there were 7 puppies available for adoption.

Varvara68 [4.7K]

A. 3 hours is the answer

3 0

3 years ago

Read 2 more answers

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago

Z=(x-u)/q slove for x

frosja888 [35]

Answer:

zq+u =x

Step-by-step explanation:

z=(x-u)/q

Multiply each side by q

zq = (x-u)/q *q

zq = x-u

Add u to each side

zq+u = x-u+u

zq+u =x

6 0

3 years ago

If Lylah completes the square for f(x) = x 2 + 24x -18 in order to find the minimum, she must write f(x) in the general form f(x

olga nikolaevna [1]

Answer:

Step-by-step explanation:

F(x)= (x − a)2 + b

Rewrite the equation as (X-a)2 + b= f(X) (X-a)2 + b= f(X) subtract (x-a)^2 from both sides of the equation b=f(x)- (x-a)^2

3 0

3 years ago