Answer:
the square of greater side is equal to the sum of two other side in right angled rectangle
Step-by-step explanation:
also known as trigonometry of Pythagoras.
Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.
Step-by-step explanation:
Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.
Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.
Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB
⇒ 6/x = 12/6
⇒ 6/x = 2
⇒ x = 3 inches
Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.
⇒ 
⇒
⇒
⇒
⇒
⇒AD = 5 inches
Answer:
A. 49 feet
B. 66 feet (round to the nearest foot)
C. 4 seg
Step-by-step explanation:
A. What is the height of the ball after 3 seconds?
For 


B. What is the maximum height of the ball? round to the nearest foot

then

For 

C. When will the ball hit the ground?
The ball will hit the ground when 
so, 
Using the quadratic equation

An entire amount is 100%.
If you decrease it by 20%, you end up with 80% of the entire amount.
To find 80% of an amount, multiply the amount by 0.8
Answer: multiply by 0.8