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sweet-ann [11.9K]
2 years ago
5

What is the solution of the equation 3x + 5 + 2x - 12

Mathematics
2 answers:
ss7ja [257]2 years ago
5 0

Answer:

7/5

Step-by-step explanation:

3x + 5 + 2x - 12 = 0

5x - 7 = 0

5x = 7

x = 7/5

Papessa [141]2 years ago
3 0
3x + 5 + 2x -12 = 5x -7 = 5/7
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What’s the length of the new fence?
natulia [17]
We apply the Pythagorean theorem twice and obtain:
 12 ^ 2 = x ^ 2 + (15-d) ^ 2
 9 ^ 2 = x ^ 2 + d ^ 2
 We observe that it is a system of two equations with two unknowns whose solutions are:
 (x, d) = (-36/5, 27/5)
 (x, d) = (36/5, 27/5)
 We ignore the negative solution, therefore, the solution is:
 (x, d) = (36/5, 27/5)
 Answer:
 
The length of the new fence is:
 
x = 36/5 meters
7 0
3 years ago
Pls help, and explain. I will give brainliest
-BARSIC- [3]

Answer:

Nicole should take 13 1/8 cups of snack mix.

Step-by-step explanation:

If a serving size is 7/8 and Nicole wants to take 15 serving sizes (15 7/8's), then we must multiply 7/8 by 15:

15 × 7/8

Write 15 over 1 (15 = 15/1) to make the calculations easier:

15/1 × 7/8

Multiply the numerators and denominators separately:

15 × 7 / 1 × 8

105 / 8

Instructions don't say you have to do this but I will convert this improper fraction into a mixed number:

105/8 = 13 1/8

5 0
3 years ago
Need help asap please
Anarel [89]

Answer:

according to my observation it should be a option

4 0
3 years ago
How to do this problem
AlexFokin [52]

Answer:

y=3/8x - 6/7

Step-by-step explanation:

slope intercept is y=mx+b where m=the slope and b=the y intercept

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6 0
3 years ago
50 POINTS FIRST GOOD ANSWER GETS BRAINLIEST
Inessa [10]

Answer:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

Step-by-step explanation:

We are given the function:

f(x)=3+|2x-5|

Remember that by the definition of absolute value:

\displaystyle |x|= \left\{        \begin{array}{ll}            x & \quad x \geq 0 \\        -    x & \quad x < 0        \end{array}    \right.

Our absolute value is:

|2x-5|

First, we will find when it becomes 0. Set the equation equal to 0:

2x-5=0

Solve for <em>x: </em>

<em />x=5/2<em />

<em />

So, we can see that for all values greater than <em>x </em>= 5/2, 2x - 5 is positive.

For all values less than <em>x </em>= 5/2, 2x - 5 is negative.

Therefore (the positive case go above, and the negative case go below):

|2x-5|= \left\{        \begin{array}{ll}            2x-5 & \quad x \geq 5/2 \\           -(2x-5) & \quad x < 5/2         \end{array}    \right.

Finally, we can add a three:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            3+(2x-5) & \quad x \geq 5/2 \\            3+(-(2x-5)) & \quad x < 5/2        \end{array}    \right.

Simplify if desired:

f(x)=3+|2x-5|=\left\{        \begin{array}{ll}            2x-2& \quad x \geq 5/2 \\            -2x+8 & \quad x < 5/2         \end{array}    \right.

5 0
2 years ago
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