Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4
Romashka [77]
The triangles ABC and A'B'C' are shown in the diagram below. The transformation is a reflection in the line
. This is proved by the fact that the distance between each corner ABC to the mirror line equals to the distance between the mirror line to A'B'C'.
Given:
diameter = 14 inches
radius = 14 inches / 2 = 7 inches
Circumference of a circle = 2 π r = 2 * π * 7inches = 14 inches * π
Area of a circle = π r² = π * (7in)² = π * 49in²
C = 14π and A = 49π
Answer:
D.) f(m)=27−3m
Step-by-step explanation:
Given that:
Original rating = 27
Total possible rating points = 30
Drop in rating point per month = 3
m = number of months since release :
Hence,
F(m) = original rating - drop in rating per month * number of months since release
F(m) = 27 - 3(m)
F(m) = 27 - 3m
Answer:
Step-by-step explanation:
A(3,-2) ; B(6,-2)
![AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%286-3%29%5E%7B2%7D%2B%28-2-%5B-2%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B3%5E%7B2%7D%2B%28-2%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B0%7D%3D%5Csqrt%7B9%7D%5C%5C%5C%5C)
AB = 3 units
B(6,-2) ; C(6,5)
![BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%286-6%29%5E%7B2%7D%2B%285-%5B-2%5D%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%285%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%287%29%5E%7B2%7D%7D%5C%5C)
BC = 7 units
Area of rectangle = length * width
= AB * BC
= 3 * 7
= 21 square units
V=LWH
LW=area of base
V=H*areaofbase
V=2.88
areaofbase=1.44
2.88=height times 1.44
divide 1.44
2=height
2 centimeters
