Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
The simplified polynomial is x^3 y^2 -x^2 y^3 +xy
The value is -186
Step-by-step explanation:
To solve, we will need to plug in -5 for x in both instances.
|-5 + 2| / -5 + 2
|-3| / -3
Now, these absolute value bars may be a bit puzzling. What we have to do is take the absolute value of the number inside of the brackets. Meaning, that if the number is negative, we make it positive, and if the number is positive, then it stays positive.
3 / -3
-1
Hope this helps!! :)
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2^n - 3 = 83
<span>2^n = 86 </span>
<span>ln(2^n) = ln(86) </span>
<span>n*ln(2) = ln(86) </span>
<span>n= ln(86)/[ln(2)] (which is the same as "log base 2 of 86") </span>
<span>n= 6.426264755</span>
(Interchange the x and y-values)
(Solve for y)
