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Andrei [34K]
2 years ago
15

A roll of tape has a circumference of 19 centimeters. The circumference decreases 4 centimeters after you use some of the tape.

What is the diameter of the roll after you use the tape?
QUICK PLS
Mathematics
1 answer:
olga_2 [115]2 years ago
8 0

Answer:

4.77 cm correct to the nearest hundredth.

Step-by-step explanation:

The new circumference = 19 - 4 = 15 cm.

Circumference C = π * diameter

So the diameter =  C/π = 15/π = 4.7746 cm

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If an average orange weighs 75 g, how many oranges would weigh 4.5 kg?​
sashaice [31]

Answer: 60 oranges

Step-by-step explanation:

<u>Given information</u>

Weight = 75 g / orange

Total = 4.5 kg

<u>Given formula</u>

Total = Number of oranges × Average weight

<u>Convert Kilogram unit to Gram</u>

1 kg = 1000 g

4.5 kg = 4.5 × 1000 = 4500 g

<u>Substitute values into the given formula</u>

Total = Number of oranges × Average weight

Number of oranges = Total / Average weight

Number of oranges = 4500 / 75

<u>Simplify by division</u>

\Large\boxed{Number~of~oranges~=~60}

Hope this helps!! :)

Please let me know if you have any questions

5 0
2 years ago
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ivann1987 [24]

Answer:

9. 7/2

10. -6

Step-by-step explanation:

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3 years ago
What is the answer to 7 8 ÷ 3 8
devlian [24]
2.05263158 is the answer
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Simplify 10/12 to it's smallest
Rom4ik [11]
I think that the answer is 
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6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi
Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of p = 1 - 0.85 = 0.15

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

So

P = 0.15P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597

So

P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390

3.90% probability that the third failure will occur on the tenth component tested

5 0
3 years ago
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