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3 years ago

3.14 times 16 divided by 3

Mathematics

1 answer:

AleksAgata [21]3 years ago

5 0

Answer:

The answer is 16.746667

Step-by-step explanation:

1) Simplify 3.14 × 16 to 50.24.

$50.24 \div 3$

2) Simplify 50.24 ÷ 3 to 16.746667.

$16.746667$

Therefor. the answer is 16.746667.

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John has 15 1/4 gallons of gas in his truck. John can drive his truck 7 1/2 miles on each gallon of gas. About how many miles ca

photoshop1234 [79]

Answer:

114 3/8 gallons

Step-by-step explanation:

To solve the question, we multiply by the number of gallons and the amount travelled per gallon:

Let's convert all fractions to improper fractions:

15 1/4 = (15*4 + 1)/4 = 61/4

7 1/2 = (7*2 + 1)/2 = 15/2

Multiply the numerators and the denominators:

61/4 * 15/2 = 61*15/4* 2 = 915/8 = 114 3/8

-Chetan K

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3 years ago

600,000 equals how many ten thousands

Yakvenalex [24]

Divide 600,000 by 10,000.

Equals 60!

Answer is 60.

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4 years ago

Trapezoid W′X′Y′Z′ is the image of trapezoid WXYZ under a dilation through point C.

erma4kov [3.2K]

That would be the ratio of 2 corresponding sides

= 6/8

= 3/4 answer

6 0

3 years ago

The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP

Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d } = 30

5(2a + 4d )d = 60

10a + 20d = 60

reduce to lowest term to easy calculation by dividing through by 10

a + 2d = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉ = ⁹/₂(2a + 8d ) = 69

9(2a + 8d ) = 30 + 69

18a + 72d = 99 x 2

18a + 72d = 198

divide through by 18 to reduce to lowest time

a + 4d = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

a + 2d = 6

a + 4d = 11

-2d = -5

d = ⁵/₂.

Now substitute for d to get a

a + 2(⁵/₂) = 6

a + 5 = 6

a = 6 - 5

a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0

3 years ago

Aroon is asked to choose five integers so that the mode is 2 more than the median and the mean is 2 less than the median.

torisob [31]

The mean is the sum of observations divided by number of observations.

x bar = (∑x)/n
The median is the middle value of the ordered data or the value of the interval n+1/2 for odd numbered data.
The mode is the repeated value.

<h3>The highest value is 0</h3>

Number of observations= n= 5
Median is the 3rd value when the data is arranged.
Mode is unknown

The relation between Mean, Median and mode is given by

Mode= 3 Median - 2Mean---- equation1

According to the given condition

Mode= 2+median ----- equation 2

Putting equation 2 in equation 1

2+median= 3 Median - 2Mean

2 Mean= 3 Median - 2- Median

2 Mean= 2 Median - 2

Mean= Median-1

Mean- Median=1--------Eq. A

According to the second condition

Median- Mode=-2-----------eq. 3

Putting eq. A in eq. 3

Mean -1 - Mode=-2

Mean- Mode=-1

Mode- Mean=1------equation 4

Adding equation A and equation4

Mode- Mean=1

Mean- Median=1

Mode+ Median =2------- equation5

Again Putting equation2 in equation 5

2+median + Median =2

2 Median =2-2

2 Median =0

Median=0

Mean= 0-1

Mean= 0-1=-1

Mode- Mean=1

Mode-(-1)=1

Mode=0

Putting values in the formula of mean

x bar =∑x/5

(-1)5 = 0+0+ x1+x2+0

-5= x1+x2

So the highest value is 0.

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3 years ago