, and . Subtract this from the numerator and you get a remainder of
, and . Subtract this from the previous remainder and you get a new remainder of
, and . Subtract this from the previous remainder and you get a new one of
, and . Subtract this from the previous remainder and you get a new one of
doesn't divide 120, so we're done, and putting everything together we've shown that
Answer:
The equation would be B) y = 5x + 17
Step-by-step explanation:
To start, you need to locate the slope of the first equation. Since the slope is the coefficient of x, we know it to be -1/5. Now, the perpendicular slope is the opposite and reciprocal of that, which makes the new slope 5.
Now that we have this, we can use the point and the slope in point-slope form to get the equation.
y - y1 = m(x - x1)
y - 7 = 5(x + 2)
y - 7 = 5x + 10
y = 5x + 17
Answer:
Step-by-step explanation:
- A) 5x⁴ + 3x – 7 ⇒ degree 4 in standard form
- B) 2 + 4x² + 5x³ ⇒ degree 3 <u>not</u> in standard form
- C) 3x⁵ + 3x² + 6 ⇒ degree 5 in standard form
- D) 3x + 2x² – 6x⁵ ⇒ degree 5 <u>not</u> in standard form
I don’t get what your supposed to do
Let the numbers be x and y
According to the data : xy=-15 and x+y=-7
xy=-15
x+y=-7
y=-7-x
x(-x-7)=-15
y=-7-x
-x^2-7x=-15
y=-7-x
x^2+7x-15=0
y=-7-x
x=(-7±sqrt(7*7+4*15))/2
y=-7-x
x=(-7±sqrt(109<span>))/2
</span>
Goes to two systems.
1)
y=-7-x
x=(-7+sqrt(109<span>))/2
</span>
y=-7+3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
y=-3.5-sqrt(109<span>))/2
</span>x=(-7+sqrt(109<span>))/2
</span>
2)
y=-7-x
x=(-7-sqrt(109<span>))/2
</span>
y=-7+3.5+sqrt(109))/2
x=(-7-sqrt(109))/2
y=-3.5+sqrt(109))/2
x=(-7-sqrt(109<span>))/2</span>