Question

If 10^2y = 25, then 10^-y equals:(a) -1/5(b) 1/625(c) 1/50(d) 1/25(e) 1/5​

Answer 1

given:

$10 ^{2y} = 25$

to find:

${10}^{y} = .......$

solution:

$10 ^{2y} = 25$

$(10y {)}^{2} = {5}^{2}$

$10y = 5$

$\frac{1}{ {10}^{y} } = \frac{1}{5}$

${10}^{ - y} = \frac{1}{5}$

therefore, the correct answer is option E.

Answer 2

the correct option is option e.

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