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3 years ago

Please answer this question as fast as you can

Mathematics

1 answer:

WITCHER [35]3 years ago

8 0

Answer:

the answer should be a i hoped this helped\

Step-by-step explanation:

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12/21 in its simplest form

UNO [17]

12/21 in its simplest form is 4/7.

To find this out we need to divide the numerator and denominator by the GCF of 12 and 21 which is 3.

12/21

12 ÷ 3 = 4
21 ÷ 3 = 7
4/7

12/21 in its simplest form is 4/7.

12/21 = 4/7

5 0

3 years ago

Read 2 more answers

(-3,2) and ( 2,-13) slope intercept equation

Georgia [21]

Given:

The points are (-3, 2) and (2, -13).

To find:

Slope-intercept form of the equation.

Solution:

Here $x_1=-3, y_1=2, x_2=2, y_2=-13$ .

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-13-2}{2-(-3)}$

$$m=\frac{-15}{5}$

m = -3

Using point-slope formula:

$y-y_1=m(x-x_1)$

$y-2=-3(x-(-3))$

$y-2=-3(x+3)$

$y-2=-3x-9$

Add 2 on both sides.

$y-2+2=-3x-9+2$

$y=-3x-7$

Slope-intercept form of the equation is y = -3x - 7.

8 0

3 years ago

The table represents an exponential function.

nasty-shy [4]

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3 years ago

Maria has $11 to buy fish for her aquarium. Each goldfish costs $2. How many goldfish can she buy? Do not include units in your

Semmy [17]

Answer:She can buy 5 goldfish.

Step-by-step explanation: If you divide the amount of money she has to spend by the cost of the goldfish;

$11/5 = 5.5

Since she can’t buy 5 and a half goldfish, she can only buy 5.

7 0

3 years ago

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Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$