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Leya [2.2K]
3 years ago
10

A circle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that

apply. (x – 12)2 y2 = 12 (x – 6)² y² = 36 x² y² = 12 x² y² = 144 (x 6)² y² = 36 (x 12)² y² = 144
Mathematics
1 answer:
wariber [46]3 years ago
5 0

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle has a diameter of 12 units. Hence, radius = 12/2 = 6 units.

The center of the circle is at x axis (*, 0), the equation could be:

(x - 6)² + (y - 0)² = 6²

(x - 6)² + y² = 36

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

Find out more on equation at: brainly.com/question/2972832

#SPJ4

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<u>Answer:</u>

37th term of given arithmetic sequence a_1 = 2.3; d = -2.3 is -80.5.

<u>Solution:</u>

Given that  

Need to determine 37th term, when a_1 = 2.3, d = -2.3

Means first term of arithmetic sequence = a_1 = 2.3 and common difference d = -2.3

<u><em>Formula for nth term of arithmetic sequence is  </em></u>

\mathrm{a}_{\mathrm{n}}=\mathrm{a}_{1}+(\mathrm{n}-1) \mathrm{d}  --- equation 1

\text { In our case } a_{1}=2.3, d=-2.3

We need to determine 37th term so n = 37.

On substituting given values in equation (1) we get

\mathrm{a}_{37}=\mathrm{a}_{1}+(37-1) \mathrm{d}

\begin{array}{l}{\Rightarrow a_{37}=2.3+(37-1)(-2.3)} \\\\ {\Rightarrow a_{37}=2.3(1-36)=2.3 \times 35=-80.5}\end{array}

Hence 37th term of given arithmetic sequence is -80.5

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