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Leya [2.2K]
2 years ago
10

A circle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that

apply. (x – 12)2 y2 = 12 (x – 6)² y² = 36 x² y² = 12 x² y² = 144 (x 6)² y² = 36 (x 12)² y² = 144
Mathematics
1 answer:
wariber [46]2 years ago
5 0

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle has a diameter of 12 units. Hence, radius = 12/2 = 6 units.

The center of the circle is at x axis (*, 0), the equation could be:

(x - 6)² + (y - 0)² = 6²

(x - 6)² + y² = 36

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

Find out more on equation at: brainly.com/question/2972832

#SPJ4

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4 0
3 years ago
In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
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a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

\frac{20!}{18!2!}=190

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

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