Answer:
At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.
Step-by-step explanation:
If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:
2 km / 3 min = 0.666 km per minute (2/3 x 2)
0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)
Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.
Area of <span>parallelogram=base * height
so it is 12*9=108 yd²</span>
In order to factor this, we will need to take something out to get it to factor. Lets take out a greatest common factor, in this case our greatest common factor will be 3.
We will then write it as:
-3(5t+2)
Answer:
x= 37.5°
Step-by-step explanation:
∠CBD
= 180° -75° (adj. ∠s on a str. line)
= 105°
∠BCD= ∠BDC (base ∠s of isos. △BCD)
∠BCD= x
∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)
x +x +105°= 180°
2x= 180° -105°
2x= 75°
x= 37.5°
<u>Alternative</u><u> </u><u>working</u><u>:</u>
∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)
∠BDA= 52.5°
∠BDA +∠BDC= 90°
52.5° +x= 90°
x= 90° -52.5°
x= 37.5°
Answer:
1. 
( in this inequality, the time can be less than or equal to 45, but no more than 45)
2. 
(Mario's height is more than 60.)
3. 
(More than 8000 fans attended.)
