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ad-work [718]
2 years ago
10

Can someone please answer this, ill give you brainliest Would be very appreciated.

Mathematics
2 answers:
Troyanec [42]2 years ago
8 0

Answer:

See below ~

Step-by-step explanation:

Equation of Graph A :

  • No x-intercepts
  • Y-intercept at (0, 4)
  • <u>y = x² + 4</u>

<u></u>

Equation of Graph B :

  • x-intercepts at (-2, 0) and (2, 0)
  • y = (x - 2)(x + 2)
  • <u>y = x² - 4 </u>

<u></u>

Equation of Graph C :

  • opens downwards ⇒ coefficient of x² is -ve
  • x-intercepts at (-1, 0) and (1, 0)
  • y = - (x + 1)(x - 1)
  • y = -x² + 1
  • <u>y = 1 - x²</u>
kupik [55]2 years ago
4 0

For the function: y = x² + 4

  • y intercept: (0, 4)
  • x intercept: None
  • vertex: (0, 4)

For the function: x² - 4

  • y intercept: (0, -4)
  • x intercept: (-2, 0) and (2, 0)
  • vertex: (0, -4)

For the function: 1 - x²

  • y intercept: 1
  • x intercept: (1, 0) and (-1, 0)
  • vertex: (0, 1)

Conclusion:

green line = x² + 4;  blue line = x² - 4; black line = 1 -x²

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Ryan's unpaid credit card balance was $1853.68. His APR is 24.9%. What is his new balance after he makes one new transaction for
nataly862011 [7]

Answer:

  $2070.14

Step-by-step explanation:

Credit card terms vary, as do methods of computing interest and new balance. Here, we'll assume that no payment has been made (<em>in violation of the terms of the credit card</em>), and that the finance charge is only applied to the previous balance.

The finance charge is ...

  $1853.68 × 0.249 ÷ 12 = $38.46 . . . . . . . the monthly rate is 0.249÷12

Then the new balance will be the sum of the previous balance, finance charge, and new transaction(s):

  $1853.68 +38.46 + 178.00 = $2070.14

_____

<em>Comment on lack of payment</em>

Because no payment has been made, there may also be a late-payment charge added to the balance.

4 0
3 years ago
Help T-T plz (14 points)
olganol [36]

Answer:

The answer is 10.5 or 10 1/2

Step-by-step explanation:

1) A=LxW

2) the height is given but you do not have the width So Divide.

3) first turn the fraction into decimals

H= 12 1/4= 12.25

A= 128 5/8= 128.625

4) 128.625 divided by 12.25 Give you 10.5

5) you can change 10.5 into a fraction 10 1/2

hopes this helps.

8 0
3 years ago
3) The foot of a ladder is 1.2 m from a fence
VashaNatasha [74]

Answer: 4.5\ meters

Step-by-step explanation:

Using the data given in the exercise, we can draw the diagram attached, where "h" is the height of the building reached by the top of the ladder.

Notice that there are two similar triangles.

So, you can set up the following proportion:

\frac{1.8}{1.2}=\frac{h}{(1.2+1.8)}

Finally, in order to calculate the height on the building reached by the top of the ladder, you must solve for "h".

Therefore, the value of "h" is :

\frac{1.8}{1.2}=\frac{h}{3}\\\\(3)(\frac{1.8}{1.2})=h\\\\\frac{5.4}{1.2}=h\\\\h=4.5

5 0
3 years ago
Can someone help on my math test? giving out brainiest!
katovenus [111]

Answer:

None of them are correct because the circumference formula is 2pir

8 0
3 years ago
Read 2 more answers
Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T
myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5                          

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

\text{P(at least one head)} = \dfrac{7}{8} = 0.875

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5

3 0
3 years ago
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