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svetlana [45]
2 years ago
12

P(perfect square | odd)

Mathematics
1 answer:
ivann1987 [24]2 years ago
7 0
P(perfect square) is even
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Find the measure of the listed angles below.
Natali5045456 [20]

Answer:

30,90

Step-by-step explanation:

because it all adds up to 180

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Factor Completely:<br> 4x²+8x
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The answer is 4x(x+2).
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The scores on a quiz are normally distributed. The mean of the quiz is 93 and the standard deviation is 4.2. By using the Empiri
xz_007 [3.2K]

Answer:

any score that lies between 88.8 and 97.2 is within one std. dev. of the mean

Step-by-step explanation:

One std. dev. above the mean would be 93 + 4.2, or 97.2.  One std. dev. below the mean would be 93 - 4.2, or 88.8.

So:  any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.

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3 years ago
Help.? geometry basics homework 2: segment addition postulate
Neporo4naja [7]

The value of x is 3 given that ST = 8x + 11 and TU = 12x-1

The point that bisects a line divides the line into two equal parts

If T is the midpoint of SU, the following are true:

  • ST = TU
  • ST + TU = SU

Given the following

ST = 8x + 11

TU = 12x-1

Since ST = TU

8x+11 = 12x-1

8x - 12x = -1 - 11

-4x = -12

x = 12/4

x = 3

Hence the value of x is 3 given that ST = 8x + 11 and TU = 12x-1

Learn more here: brainly.com/question/17204733

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3 years ago
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Find the slope of the line that passes through the points (0,-11) and (8,-8).
Korolek [52]

To find the slope of a line, we can use the following formula:

\displaystyle \large{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:

\displaystyle \large{(x_1,y_1) = (0, - 11)} \\  \displaystyle \large{(x_2,y_2) = (8, - 8)}

Substitute the points in formula:

\displaystyle \large{m =  \frac{ - 8 -( - 11)}{ 8 - 0} }

Negative multiply negative always come out as positive.

\displaystyle \large{m =  \frac{ - 8  +  11}{ 8 - 0} } \\  \displaystyle \large{m =  \frac{ 3}{ 8 } } \\

Since m stands for slope, we can say that:

\displaystyle  \large \boxed{ \tt{slope  =  \frac{3}{8} }}

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