Answer:
One plane has a speed of 450 km/h and the other has a speed of 900 km/h.
Step-by-step explanation:
I am going to say that:
The speed of the first plane is x.
The speed of the second plane is y.
One plane is flying at twice the speed of the other.
I will say that y = 2x. We could also say that x = 2y.
Two airplanes leave an airport at the same time, flying in the same direction
They fly in the same direction, so their relative speed(difference) at the end of each hour is y - x = 2x - x = x.
If after 4 hours they are 1800 km apart, find the speed of each plane
After 1 hour, they will be x km apart. After 4, 1800. So
1 hour - x km apart
4 hours - 1800 km apart
4x = 1800
x = 1800/4
x = 450
2x = 2*450 = 900
One plane has a speed of 450 km/h and the other has a speed of 900 km/h.
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
This is easy. You just add all the like terms
Answer:
-18 C°
Step-by-step explanation:
Warmed means add cooled means subtract
starting at -23 it warmed by 8 add 8
-15
it warmed by 3 more add 3
-12
then it cooled by 6 subtract 6
-18
Answer: 7 feet
Step-by-step explanation:
Since all 4 sides of a square are equal, you do 28 / 4 = 7 feet, which is the answer.