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hjlf
2 years ago
7

50 POINTS! Use the Parabola tool to graph the quadratic function.

Mathematics
2 answers:
Ray Of Light [21]2 years ago
7 0

Answer:

See below ~

Step-by-step explanation:

Given :

f(x) = (x+4)² − 6

f(x) = a(x + h)² + k

  • The vertex of the graph is (-4, -6)
  • Compressibility factor (a) is equal to 1

Another point on the parabola :

  • Take x = 1
  • f(1) = (1 + 4)² - 6
  • f(1) = 25 - 6
  • f(1) = 19
  • The second point is (1, 19)

Graph :

kkurt [141]2 years ago
5 0

General equation

  • y=a(x-h)²+k

By observing y=(x+4)²-6

  • Vertex is at (-4,-6)
  • a is 1

So

The parabola graph is attached

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Solve the system using substitution: y + 8x = 10 and 2y - 4x = 40
exis [7]

Answer:

Hence x = -1 and y = 18

<em></em>

Step-by-step explanation:

Given the system of equations

y + 8x = 10... 1

2y - 4x = 40 ... 2

From 1; y = 10-8x

Substitute into 2;

2(10-8x) - 4x = 40

20 - 16x - 4x = 40

20 - 20x = 40

-20x = 40 - 20

-20x = 20

x = -1

Recall that y = 10-8x

y = 10 - 8(-1)

y = 10 + 8

y = 18

Hence x = -1 and y = 18

<em></em>

4 0
3 years ago
Which quadratic equation has a vertex at (4, 2)?
kenny6666 [7]

Answer:

use mathaway or algebra calculator they help alot

7 0
3 years ago
Super easy question just don’t know it
Doss [256]

Answer:

Integer

Step-by-step explanation:

6 0
3 years ago
Use the explicit formula an=a1+(n-1)
Anestetic [448]
See the attached picture for the solution:

4 0
3 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
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