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Elza [17]
3 years ago
13

the post for Nancy's gazebo form a regular hexagon what is the measure of the angle formed at Each corner of the gazebo ​

Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer: 120 degrees, the total is 720 degrees, so that divided by 6 is 120

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Please help
Gnesinka [82]

Answer:

1. subtract 9 from z- z-9

2. add 9 and z - z+9

3. divide 9 by z - 9/z

4. multiply 9 by z - 9z

Step-by-step explanation:

Your welcome!

Brainliest Appreciated!

7 0
2 years ago
Read 2 more answers
Which two equations are parallel?
Mekhanik [1.2K]

Answer: The third option is correct.

Step-by-step explanation:

In order for two equations to be parallel, the equations' slopes must be the same.

5 0
2 years ago
A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the v
monitta
Let number of  fives = x then number of ones = 3x  and number of tens = x - 1

so we can create the equation 

x + 3x +  x-1 + y = 26  where y = number of twenties
so
5x + y = 27

also we have the equation 

5x + 3x + 10(x - 1) + 20y = 120

18x + 20y = 130..................................(1)
5x    + y    = 27     multiply  by -20:-
-100x - 20y = -540..............................(2)
Adding equation (1) and (2)
-82x = -410
x  = 5,  that is  5 fives

Now plug x = 5 into equation 1:-
18(5) + 20y = 130
20y =  40
y =  2 ,   that is 2 twenties

So the answer is   there are (3x) = 15 ones , 5  fives, 4 tens and 2 twenties
7 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS
gayaneshka [121]

Answer:

( 1, -2)

step-by-step explanation:

  • original coordinates of C: (4, -2)

if reflected over y-axis: use the formula: (x,y) → (-x,y)

  • new coordinates: (-4, -2)

then if translated 5 units horizontally, there will be change in x axis:

  • new coordinates: (-4+5, -2) → ( 1, -2)
7 0
2 years ago
A prize wheel is divided into 12 equally likely spaces labeled 1 to 12.
ikadub [295]

Answer:

Events E and F are independent.

Step-by-step explanation:

E = {multiple of 3}  = {3, 6, 9, 12}

P(E) = 4/12

F = {even number}  = {2, 4, 6, 8. 10, 12}

P(F) = 6/12

E and F = {even and multiple of 3} = {6, 12}

P(E∩F) = 2/12

In order for two events to be independent the following relationship must be true:

P(E)*P(F) = P(E\cap F)

Testing this property:

P(E)*P(F) = \frac{4}{12}*\frac{6}{12}=\frac{24}{144}=\frac{1}{6}    \\P(E\cap F) = \frac{2}{12}=\frac{1}{6} \\P(E)*P(F) = P(E\cap F)

The relationship holds true, thus events E and F are independent.

4 0
3 years ago
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