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zavuch27 [327]
3 years ago
9

The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b

y a normal distribution with a mean value of 150 sec and a standard deviation of 25 sec. The fastest 10% are to be given advanced training. What task times qualify individuals for such training? (Round the answer to one decimal place.)
________ seconds or less
Mathematics
1 answer:
Gala2k [10]3 years ago
3 0

Answer:

214.5 seconds or less time will qualify individuals for such training

Step-by-step explanation:

given that the time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 150 sec and a standard deviation of 25 sec.

i.e. X the time that it takes a randomly selected job applicant to perform a certain task is N(150,25)

The fastest 10% are the ones who are above the 90th percentile

We know 90th percentile for Z std normal score is 1.28

Corresponding X score would be

x=\mu+1.28 \sigma\\X= 150+1.28(25)\\= 214.50

Round off to one decimal

214.5 seconds or less time will qualify individuals for such training

You might be interested in
The lsrl after an exponential transformation is log yhat=.4785 + 1.468x. What is the exponential form of the regression?
zheka24 [161]

Answer:

10^{0.4785+1.468x}=y

Step-by-step explanation:

So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: log(y)=0.4785+1.468x. And generally a logarithm can be written in the form log_ba=c which can then be rewritten as b^c=a, but since the log has no base, it's assumed to be 10. So in this case you have the equation:

log_{10}y=0.4785+1.468x, which can then be written in exponential form as:

10^{0.4785+1.468x}=y

8 0
2 years ago
El numero de libros vendidos en una tienda aumentó aproximadamente de 6000 a 9000 durante varios meses cual porcientorepresenta
Aleksandr-060686 [28]

Answer:

50%

Step-by-step explanation:

To calculate the percentage of increase, what we must do divide the two quantities, in this way we will be able to know how bigger they are from each other. So:

9000/6000 = 1.5

Now, we subtract those from 1, which would be 100%

1.5 - 1 = 0.5

therefore the increase was 50%

6 0
3 years ago
Please can u answer all the questions!!! Thank u soo much
DiKsa [7]

4.a) 2x=7*3

2x=21

x=21/2 OR

x=10.5

4.b)5x=25*6

5x=150

x=150/5

x=30

4.c)4x=5*14

4x=70

x= 70/4

x=17.5

4.d)4x=9*3

4x=27

X=27/4

X=6.75

4.e)x=0.05*3

X=0.15

4.f)x=0.25*7

X=1.75

4.g)x=0.4*1.5

X=0.6

4.h)x=0.7*2.2

X=1.54

5a)x/7=7-3

X/7=4

X=4*7

X=28

B)2x/5=3+8

2x/5=11

2x=11*5

2x=55

X=55/2

X=27.5

C)2x/3=74-26

2x/3=48

2x=48*3

2x=144

X=72

(I can’t finish all but it is the same method )

5 0
3 years ago
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
zzz [600]

Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

Null Hypothesis : Xbar = mu

Alternate Hypothesis : Xbar > mu

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 30 ) /(0.689/sqrt(6))

= 4.372

P-value = ~0

Since P-vale < 0.01 , we will reject null hypothesis.

The data suggest that true average stopping ditance exceeds the maximum.

b)

i) SD = 0.65

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.65/sqrt(6))

= 0.867

P-value = 0.3859 Answer

ii) SD = 0.65

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.65/sqrt(6))

= -2.9

P-value = 0.0037 Answer

c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

4 0
3 years ago
WILL GIVE BRAINLIEST. If x+y=3 and 3x+5y=13, then x-y is equal to?
Alex17521 [72]

Answer:

(1,2)

y=2

x=1

Step-by-step explanation:

x+y=3

3x+5y=13

solve the equation

x=3-y

3x+5y=13

substitute the value of x into an equation

3(3-y)+5y=13

distribute

9-3y+5y=13

add -3y to 5y

9+2y=13

subtract 9 from both sides

2y=4

divide both sides by 2

y=2

substitute the value of y into an equation

x=3-2

subtract 3 to 2

x=1

--------

(1,2)

--------

6 0
3 years ago
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