Answer is c because if count the sides of how many spaces are there
The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.
Answer:
x = 14
Step-by-step explanation:
The polygon given has 6 sides
Sum of interior angles of a 6-sided polygon = 180(n - 2)
substitute n = 6 into 180(n - 2)
Sum of the polygon = 180(6 - 2) = 720°
Thus:
10x + 8x - 16 + 12x - 8 + 7x + 2 + 9x + 4 + 6x + 10 = 720
Add like terms
52x - 8 = 720
52x = 720 + 8
52x = 728
x = 728/52
x = 14
For your first one it’s definitely 94$
