Question

Can you help me solve this question? (Also explain me how is it possible)

Answer 1

Answer:

Answer B) (2 times )

Step-by-step explanation:

Let's start with the person that shook hands more (Dora), so we already know how four of this connections took place See attached image.

step 1:

D is connected to A, B, C, and E

Step 2:

Now proceed with the connections for the second greatest (C who shook hands with 3 people). Notice that C is already connected with D, and can connect with B and with E, but NOT with A (since this person shook hands only once - with D. So C is connected to B, D, and E completing the three handshakes.

step 3: Now just corroborate that B is already connected to two people (C and D).  So just count the number of connections that E is left with: 2 handshakes.

Answer 2

Answer:

( E ) 0

Step-by-step explanation:

Solution:-

- There can be two ways in solving this question. Either we lay-out a map of every person ( Alan, Bella, Claire, Dora, and Erik ) shaking hands with each other.

- We will use an intuitive way of tackling this problem.

- We have a total of 5 people who greeted each other at the party.

- Each of the 5 people shook hands exactly " once "! We can give this a technical term of " shaking hands - without replacement ".

- We will define our event as shaking hands. It takes 2 people to shake hands.

- We will try to determine the total number of unique "combinations" that would result in each person shaking hands exactly one time.

- We have a total of 5 people and we will make unique combinations of 2 people shaking hands. This can be written as:

                            5C2 = 10 possible ways.

- So there are a total of 10 possible ways for 5 people to greet each other exactly once at the party.

- We are already given the data for how many handshakes were made by each person as follows:

                      Name                 Number of handshakes

                       Alan                                   1

                       Bella                                  2

                       Claire                                 3

                       Dora                                   4

               =======================================

                      Total                                  10

               =======================================

- So from the data given. 10 unique hand-shakes were already done by the time it was " Eriks " turn to go and greet someone. This also means that Erik has already met all 4 people in that party. So he doesn't have to approach anyone to shake hands and know someone. He is already been introduced to rest of 4 people in the group.

Answer: Erik does not need to shake hands with anyone! He is known and greeted rest of the 4 people on the group.