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Aleonysh [2.5K]
3 years ago
10

The line y=2/5x +7 is dilated by a scale factor of 4 centered at the point (5,9). What equation represents the image of the lone

after the dilation?
Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

Step-by-step explanation:

I don’t understand

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A volleyball player serves the ball from a height of 6.5 feet above the ground with an initial vertical velocity of 21 feet per
Vaselesa [24]

Answer:

Option D. H(t) = 6.5+21t-16t^2

Step-by-step explanation:

we know that

If air resistance is ignored, the height h (in feet) of the ball t seconds after it is served is given by

H(t) = - \frac{1}{2}g t^2 + V_0t + H_0

where

g is the acceleration due to gravity which on earth is approximately equal to 32 feet / sec^2

V_0 is the initial velocity (when t = 0 )

H_0 is the initial height (when t = 0)

In this problem we have

V_0=21\ ft/sec\\H_0=6.5\ ft

substitute the given values

H(t) = - \frac{1}{2}(32) t^2 + (21)t + 6.5

H(t) = -16t^2 + 21t + 6.5

Rewrite

H(t) = 6.5+21t-16t^2

3 0
3 years ago
Efectuati calculele:
NNADVOKAT [17]
\sqrt{(5 - 1)^{2}} +  \sqrt{20}

\sqrt{4^{2}} +  \sqrt{4 * 5}

\sqrt{16} +  \sqrt{4} \sqrt{5} 


4 + 2 \sqrt{5} 


4\sqrt{5} + 2 \sqrt{5} 


6 \sqrt{5}


\sqrt{(10 - 3)^{2}} +  \sqrt{20 * 18}

\sqrt{7^{2}}  +  \sqrt{4 * 9 * 5 * 2}

\sqrt{49} +  \sqrt{36 * 10}

7 +  \sqrt{36}\sqrt{10}

7 + 6\sqrt{10}

7\sqrt{10} + 6\sqrt{10}

13\sqrt{10}


\sqrt[3]{(3 + 1)^{2}} -  \sqrt{(3 - 2)x^{2}

\sqrt[3]{4^{2}} -  \sqrt{x^{2}

\sqrt[3]{16} - x[tex] \\[tex] \sqrt[3]{8 * 2} - x

\sqrt[3]{8} \sqrt[3]{2} - x


2\sqrt[3]{2} - x




8 0
3 years ago
If m&lt;BDC = 20, m arc AB = 140, and marc CD = 120, find m&lt;1.<br><br>​
lara [203]

Answer:

40

ljfldnjkafkjagfbkg bkj hbsfgjhg .

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A bag contains 3 red, 4 blue, and 6 yellow marbles. One marble is selected at a time, and once a marble is selected, it is not r
astraxan [27]

The probability of choosing two yellow marbles = 5/26

Step-by-step explanation:

Step 1 :

Given

Total number of marbles in the bag = 13 marbles

Number of yellow marbles = 6.

We choose 2 marbles from the bag without replacing and need to determine the probability that both are yellow.

Step 2 :

Probability of finding yellow marble in the first try = Number of yellow marbles / Total number of marbles = \frac{6}{13}

Once the yellow marble is selected we have 5 yellow marbles among 12 remaining marbles in the bag.

Probability of finding yellow marble in the second try = Number of yellow marbles / Total number of marbles = \frac{5}{12}

Step 3:

P(yellow in first 2 tries) = P(yellow in first try) * P(yellow in second try)

P(yellow in first 2 tries) = \frac{6}{13} * \frac{5}{12} = \frac{5}{26}

Step 4:

Answer:

The probability of choosing two yellow marbles = 5/26

4 0
3 years ago
How to solve for 93,94, and 95
kvasek [131]

Answer:

93- not a triangle

94- right triangle

95- I dont know sorry!


3 0
3 years ago
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